Answer:
2625 dolls
Step-by-step explanation:
Please refer to the attached image for explanations
You need to add what the lines are if you want them to be analysed for you^^
To calculate amount accrued after a given period of time we use the compound interest formula: A= P(1+r/100)∧n where A i the amount, P is the principal amount, r is the rate of interest and n is the interest period.
In the first part; A= $ 675.54, r= 1.25% (compounded semi-annually) and n =22 ( 11 years ), hence, 675.54 = P( 1.0125)∧22
= 675.54= 1.314P
P= $ 514.109 , therefore the principal amount was $ 514 (to nearest dollar)
Part 2
principal amount (p)= $ 541, rate (r) = 1.2 % (compounded twice a year thus rate for one half will be 2.4/2) and the interest period (n)= 34 (17 years×2)
Amount= 541 (1.012)∧34
= 541 ×1.5
= $ 811.5
Therefore, the account balance after $ 811.5.
Let S and B be savings and bills respectively. Then,
S α 1/B
S = k/B Where k = Constant.
When S = $300, B = 65
Then,
300 = k/65
k = 300*65 = 19500
Therefore,
For B = $145,
S= 19500/145 = $134.48
Answer and Explanation:
Since this is an isosceles right triangle, you can use the ratio of side lengths specific to this type of triangle where both legs are the hypotenuse over root 2:
u = v = 164√2 / √2 = 164
so:
u = 164
v = 164
