Ask question

Ask question

All categories

11 months ago

14

Find the equation of the line passing through the points (3,-2) and (3, 4).The answer is x = 3. I'm just wondering how my textbo

ok got to this solution.My work:y-y1=m(x-x1). m=y2-y1 / x2-x1. y=mx+bm=4--2 / 3-3 = 6/0 = 0. m=0.y--2=0(x-3) = y=0-2 y=-2 <<<

1 answer:

Leviafan [203]11 months ago

3 0

Given two points. we can find the equation of a line passing through the points

The formula to be used is:

$\frac{y_2-y_1}{x_2-x_!}=\frac{y-y_1}{x-x_!}$

where

$x_1=3,y_!=-2,x_2=3,y_2=4$ $\frac{4-(-2)}{3-3}=\frac{y-(-2)}{x-3}$

=>

$\frac{6}{0}=\frac{y+2}{x-3}$

The next step is to cross multiply

$6(x-3)=0(y+2)$

=>

$6(x-3)=0$

Divide both sides by 6 and make x the subject

x=3

You might be interested in

Please Answer ASAP According to the table, which ordered pair is a local maximum of the function, f(x)? (0, 64) (3, –35) (5, 189

Katarina [22]

The ordered pair that represents a maximum is (5,189)

6 0

3 years ago

Hey someone help me with this please

OverLord2011 [107]

Answer:

d

Step-by-step explanation:

d. neither

If I helped please vote brainliest

6 0

3 years ago

Find the Fourier series of f on the given interval. f(x) = 1, ?7 < x < 0 1 + x, 0 ? x < 7

Zolol [24]

$f(x)=\begin{cases}1&\text{for }-7$

The Fourier series expansion of $f(x)$ is given by

$\dfrac{a_0}2+\displaystyle\sum_{n\ge1}a_n\cos\frac{n\pi x}7+\sum_{n\ge1}b_n\sin\frac{n\pi x}7$

where we have

$a_0=\displaystyle\frac17\int_{-7}^7f(x)\,\mathrm dx$
$a_0=\displaystyle\frac17\left(\int_{-7}^0\mathrm dx+\int_0^7(1+x)\,\mathrm dx\right)$
$a_0=\dfrac{7+\frac{63}2}7=\dfrac{11}2$

The coefficients of the cosine series are

$a_n=\displaystyle\frac17\int_{-7}^7f(x)\cos\dfrac{n\pi x}7\,\mathrm dx$
$a_n=\displaystyle\frac17\left(\int_{-7}^0\cos\frac{n\pi x}7\,\mathrm dx+\int_0^7(1+x)\cos\frac{n\pi x}7\,\mathrm dx\right)$
$a_n=\dfrac{9\sin n\pi}{n\pi}+\dfrac{7\cos n\pi-7}{n^2\pi^2}$
$a_n=\dfrac{7(-1)^n-7}{n^2\pi^2}$

When $n$ is even, the numerator vanishes, so we consider odd $n$ , i.e. $n=2k-1$ for $k\in\mathbb N$ , leaving us with

$a_n=a_{2k-1}=\dfrac{7(-1)-7}{(2k-1)^2\pi^2}=-\dfrac{14}{(2k-1)^2\pi^2}$

Meanwhile, the coefficients of the sine series are given by

$b_n=\displaystyle\frac17\int_{-7}^7f(x)\sin\dfrac{n\pi x}7\,\mathrm dx$
$b_n=\displaystyle\frac17\left(\int_{-7}^0\sin\dfrac{n\pi x}7\,\mathrm dx+\int_0^7(1+x)\sin\dfrac{n\pi x}7\,\mathrm dx\right)$
$b_n=-\dfrac{7\cos n\pi}{n\pi}+\dfrac{7\sin n\pi}{n^2\pi^2}$
$b_n=\dfrac{7(-1)^{n+1}}{n\pi}$

So the Fourier series expansion for $f(x)$ is

$f(x)\sim\dfrac{11}4-\dfrac{14}{\pi^2}\displaystyle\sum_{n\ge1}\frac1{(2n-1)^2}\cos\frac{(2n-1)\pi x}7+\frac7\pi\sum_{n\ge1}\frac{(-1)^{n+1}}n\sin\frac{n\pi x}7$

3 0

2 years ago

I NEED THIS PLEASE EXPERS.

kipiarov [429]

Answer: The answer is 24 :)

Give brainlest if I’m right

7 0

3 years ago

Read 2 more answers

Kareendeep has $168.50 in her bank account. She buys x shirts for $5.5o each. Write and solve an equation Kareendeep can use to

Vikentia [17]

Answer:

Equation: 5.5x = 168.5

Solution: 30 shirts

Step-by-step explanation:

First, create the equation where x is the number of shirts.

Since each shirt is $5.50, the cost of the shirts will be 5.50x

Set this equal to 168.50, since that is how much money Kareendeep has.

So, the equation will be 5.5x = 168.5

Now, solve this for x, the number of shirts she can buy:

5.5x = 168.5

Divide each side by 5.5

x = 30.6

Since we can only have a whole number of shirts, she can only buy 30 shirts.

So, the answer is 30 shirts.

5 0

3 years ago