Can you please include a question please? Thank you
You have two equations.
since the second is already isolated, sub in x-4 for every y in equation 1 so that
![x^{2} - 4 [(x-4)^{2}] =16 ](https://tex.z-dn.net/?f=%20x%5E%7B2%7D%20-%204%20%5B%28x-4%29%5E%7B2%7D%5D%20%3D16%0A%20)
expand, collect like terms, factor to find x, then plug x value back into original equation to find y
It looks like you might have intended to say the roots are 7 + i and 5 - i, judging by the extra space between 7 and i.
The simplest polynomial with these characteristics would be

but seeing as each of the options appears to be a quartic polynomial, I suspect f(x) is also supposed to have only real coefficients. In that case, we need to pair up any complex root with its conjugate to "complete" f(x). We end up with

which appears to most closely resemble the third option. Upon expanding, we see f(x) does indeed have real coefficients:

Slope = 2/5 ; Passes through (-4, -7) ; Point-slope form
point-slope form : y-y₁=m(x-x₁)
Simply plug everything in :)
Remember !! m=slope
y - (-7) = 2/3(x - (-4))
Simplify.
y + 7 = 2/3(x + 4)
*Some teachers want this simplified more so here's the simplest answer :
y + 7 = 2/3x + 8/3 *
~Hope I helped!~
<em>π</em> ≈ 3.14 > 2, so the second piece is the relevant one:
