Qualitative data gives the information of quality which can not be measured in numbers. For example: Color of eyes, softness of skin.
Quantitative data is information of quantity that can be represented in numbers. For example length and mass of any object.
Zinc is a silver-gray metal is a qualitative data, here silver gray color is quality of zinc metal which can not be measured in numbers.
Chlorine has a density of 3.2 g/L is a quantitative data. The value of density can be compared with other elements by comparing the numbers.
Gallium is not found in nature is neither qualitative nor quantitative.
Nitrogen has a melting point of –210.00 °C is a quantitative data because this is expressed in numbers.
Aluminum is a solid is a qualitative data because it tells about the state of element which can not be measured in numbers.
Answer:
option B
Explanation:
given,
diameter of the rotating space = 2 Km
Force exerted at the edge of the space = 1 g
force experienced at the half way = ?
As the object is rotating in the circular part
Force is equal to centripetal acceleration.
at the edge
g = ω² r
ω is the angular velocity of the particle
r is the radius.
now, acceleration at the half way
g' = ω² r'



People at the halfway experience g/2
hence, the correct answer is option B
Answer:
To create a second harmonic the rope must vibrate at the frequency of 3 Hz
Explanation:
First we find the fundamental frequency of the rope. The fundamental frequency is the frequency of the rope when it vibrates in only 1 loop. Therefore,
f₁ = v/2L
where,
v = speed of wave = 36 m/s
L = Length of rope = 12 m
f₁ = fundamental frequency
Therefore,
f₁ = (36 m/s)/2(12 m)
f₁ = 1.5 Hz
Now the frequency of nth harmonic is given in general, as:
fn = nf₁
where,
fn = frequency of nth harmonic
n = No. of Harmonic = 2
f₁ = fundamental frequency = 1.5 Hz
Therefore,
f₂ = (2)(1.5 Hz)
<u>f₂ = 3 Hz</u>
Answer:
14 m/s
Explanation:
u = 0, h = 10 m, g = 9.8 m/s^2
Use third equation of motion
v^2 = u^2 + 2 g h
Here, v be the velocity of ball as it just strikes with the ground
v^2 = 0 + 2 x 9.8 x 10
v^2 = 196
v = 14 m/s
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