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ki77a [65]
3 years ago
6

When a light ray passes from LESS dense water (n = 1.33) into a MORE dense diamond (n = 2.419) at an angle of 45 degrees, its pa

th is bend _____ the normal.
Physics
1 answer:
Ivenika [448]3 years ago
3 0

Towards

<u>Explanation:</u>

When light is incident at a transparent surface, the transmitted component of the light changes direction at the interface. Another component of the light is reflected at the surface. When a ray of light passes from water to diamond at an angle 45°, its path is bent towards the normal. This is so because water is less dense than the diamond. The refractive index of water (n = 1.33) is less than the refractive index of diamond (n = 2.419).

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finding Cepheid variable and measuring their periods.

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The outer planets are similar to the planet Earth; they just happen to be farther away from the Sun.
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3 years ago
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Explain how mirrors can produce images that are larger or smaller than life size, as well as upright or inverted
galina1969 [7]

Answer:

1) When d_{o} < d_{i} (hence  d_{o} < f ) and they are both in front of the mirror (positive), the image will be larger and inverted

2) When d_{o} > d_{i} (and d_{o} < f ) such that they are both positive (in front of the mirror), the image will be smaller and inverted

3) When the image is behind the mirror, for convex mirrors and the object is in front the image will be uptight. The magnification of the image will be the ratio of the image distance to the object distance from the mirror

Explanation:

The position of an object in front of a concave mirror of radius of curvature, R, determines the size and orientation of the image of the object as illustrated in the mirror equation

\dfrac{1}{f}=\dfrac{1}{d_{o}} + \dfrac{1}{d_{i}}

Magnification, \, m = \dfrac{h_{i}}{h_{o}} = -\dfrac{d_{i}}{d_{o}}

Where:

f = Focal length of the mirror = R/2

d_{i} = Image distance from the mirror

d_{o} = Object distance from the mirror

h_{i} = Image height

h_{o} = Object height

d_{o} is positive for an object placed in front of the mirror and negative for an object placed behind the mirror

d_{i} is positive for an image formed in front of the mirror and negative for an image formed behind the mirror

m is positive when the orientation of the image and the object is the same

m is negative when the orientation of the image and the object is inverted

f and R are positive in the situation where the center of curvature is located in front of the mirror (concave mirrors) and f and R are negative in the situation where the center of curvature is located behind the mirror (convex mirrors)

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4 years ago
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c.magnetic induction hope this helps
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3 years ago
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