Question

A golfer strikes her tee shot with the following velocities, vx = 106 m/s & vy = 66.2 m/s. a. What is the velocity of flight? b. The time of flight? c. The horizontal distance traveled?​

Answer 1

Answer:

a) V ≈ 125 m/s;  b) Δt = 13.24 s;  c) ΔS ≈ 1450 m

Explanation:

a) We have just to calculate the vector resultant.

V² = 106² + 66.2²

V² = 15618.44

V ≈ 125 m/s

b) The time of flight is equal to the time to reach the maximum height summed to the time to reach the land.

In vertical:

V = V₀ + a * t

V = 66.2 - g * t

0 = 66.2 - 9.8 * t

t ≈ 6.76 s

So: Δt = 13.24 s

c) In horizontal:

V = ΔS / Δt

106 = ΔS / 13.52  ⇒  ΔS = 106 * 13.52

ΔS = 106 * 13.52

ΔS = 1433,12

ΔS ≈ 1450 m