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zepelin [54]
3 years ago
9

A uniform plank of length 5.0 m and weight 225 n rests horizontally on two supports, with 1.1 m of the plank hanging over the ri

ght support (see the drawing). to what distance x can a person who weighs 450 n walk on the overhanging part of the plank before it just begins to tip
Physics
1 answer:
likoan [24]3 years ago
6 0
<span>0.7 meters from the support, or 0.4 meters from the end of the board. Another way of describing the problem is to have the 450 N person move so that the center of mass of the plank and person system is on the second support. So let's first determine how far from that support the center of mass of the plank is. We can model the plank as a point mass source that's 2.5 meters from either end. So that point mass is 2.5-1.1 = 1.4 meters from the pivot. So let's multiply that radius by the mass, getting: 1.4 m * 225 N = 315 Nm Now the person will be at just the tipping point when their mass multiplied by the distance equal 315. So let's do the division. 315 Nm / 450 N = 0.7 m So the person will be at the tipping point when he's 0.7 meter from the support, or 1.1 - 0.7 = 0.4 meters from the end of the board.</span>
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Answer:

R = 710.7N

L = 67.689 N

During gravity fall L = R = 0 N

Explanation:

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g + 0.15g = 1.15g

The force R that the elevator exerts on her feet would be product of acceleration and total mass (Newton's 2nd law):

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The force L that she exerts on the package would be:

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When the system is falling, all have a net acceleration of g. So the acceleration that the elevator exerts on the woman (and the package) is 0, and so are the forces L and R.

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3 years ago
A proton has been accelerated from rest through a potential difference of -1000 v . part a what is the proton's kinetic energy,
wlad13 [49]
We can apply the law of conservation of energy here. The total energy of the proton must remain constant, so the sum of the variation of electric potential energy and of kinetic energy of the proton must be zero:
\Delta U + \Delta K=0
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\Delta K = - \Delta U
The variation of electric potential energy is equal to the product between the charge of the proton (q=1eV) and the potential difference (\Delta V=-1000 V):
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Answer:

Explanation:

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Answer:

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