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alexandr402 [8]
4 years ago
13

Which of these is not a type of force?

Physics
2 answers:
coldgirl [10]4 years ago
6 0
Inertia
the awnswer is inertia b
Greeley [361]4 years ago
6 0

The answer is,

<u>B. inertia</u>  (:


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Why does your body feels like it is being pushed back when the car starts back up again
Llana [10]
The acceleration due to gravity is not due to the Earth's motion through space. It is due to the gravitational force pulling you towards the center of mass of the Earth. The ground pushes back<span>, and what you </span>feel<span> is </span>your<span> weight. This is the same as what you </span>feel<span> in an accelerating </span>car<span>.</span>
5 0
4 years ago
. Take a stick of length one and denote it by the unit interval [0, 1]. Pick two i.i.d. Uniform(0, 1) random variables U and V a
BartSMP [9]

Answer:

What is the expected value of L = 1/3

Explanation:

kindly check the attached file below.

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4 years ago
A 300.0-kg speedboat is moving across a lake at 35.0 m/s.
Varvara68 [4.7K]
The answer is 300kg times the 35 m/s10,500 kg•m/s
5 0
3 years ago
Read 2 more answers
What is the magnitude of the force, directed parallel to the ramp, that he needs to exert on the crate to get it to start moving
lions [1.4K]

Complete question is;

Jason works for a moving company. A 75 kg wooden crate is sitting on the wooden ramp of his truck; the ramp is angled at 11°.

What is the magnitude of the force, directed parallel to the ramp, that he needs to exert on the crate to get it to start moving UP the ramp?

Answer:

F = 501.5 N

Explanation:

We are given;

Mass of wooden crate; m = 75 kg

Angle of ramp; θ = 11°

Now, for the wooden crate to slide upwards, it means that the force of friction would be acting in an opposite to the slide along the inclined plane. Thus, the force will be given by;

F = mgsin θ + μmg cos θ

From online values, coefficient of friction between wooden surfaces is μ = 0.5

Thus;

F = (75 × 9.81 × sin 11) + (0.5 × 75 × 9.81 × cos 11)

F = 501.5 N

3 0
3 years ago
A ball is projected at an immovable wall with a speed vi and bounces back the wall in such a manner that it only has 1/3 of its
sergey [27]

The fraction of the kinetic energy of the ball lost during the collision is \frac{1}{3}.

The given parameters;

  • <em>initial speed of the ball, = vi</em>
  • <em>final momentum of the ball, Pf = ¹/₃Pi</em>

The initial and final momentum of the ball is calculated as;

P_i = m_ivi

P_f = m_fv_f = \frac{1}{3} m_iv_i

The initial and final kinetic energy of the ball is calculated as;

K.E_i = \frac{1}{2} m_iv_i^2 = \frac{1}{2} P_iv_i\\\\K.E_f = \frac{1}{2} m_fv_f^2= \frac{1}{2} (\frac{1}{3} P_iv_i)= \frac{1}{6} P_iv_i

The change in the kinetic energy is calculated as;

\Delta K.E = K.E_f - K.E_i \\\\\Delta K.E = \frac{1}{6} P_iv_i - \frac{1}{2} P_iv_i = \frac{1}{3} P_iv_i

Thus, the fraction of the kinetic energy of the ball lost during the collision is \frac{1}{3}.

Learn more here:brainly.com/question/18566218

5 0
3 years ago
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