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Kay [80]
1 year ago
3

If you thrust a magnet into a closed loop of wire, the loop will

Physics
1 answer:
snow_lady [41]1 year ago
5 0

If you thrust a magnet into a closed loop of wire, the loop will <u>have current in it</u>. So the correct option is B.

<h3>What is a magnet?</h3>

A magnet is a body with a magnetism that can attract different irons that can be given naturally or artificially. Magnets can have their magnetic field continuously and this field can attract materials or repel them, this will depend on the magnetic permeability of the compound. The magnetic field of the images will be oriented towards the south pole and the north pole and each of these will be attracted by their opposites.

Not all magnets have permanent magnetism, this depends on whether they are going to be magnetized to be permanent or if they will only have temporary functionality.

By pushing a magnet in a closed circuit of wire, a magnetic field will be generated in which a current will flow in the turns of wire.

Therefore, we can confirm that the correct option is B. have current in it.

To learn more about magnets visit: brainly.com/question/2841288

#SPJ1

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If the particles are oxygen ions carrying a charge of −2e and the magnetic field magnitude is 0.12 T , how long does it take eac
Natali5045456 [20]

Time taken by each ion to travel the semicircular path through the magnetic field is 34 X 10⁻²⁶s.

<u>Explanation:</u>

Given:

Charge of oxygen ion, q = -2

Magnetic Field, B = 0.12 T

Mass of O₂ , m= 2.6 X 10⁻²⁶ Kg

Time, T = ?

We know,

                T = \frac{2\pi m}{qB}

Therefore,

T = 2 X 3.14 X 2.6 X 10⁻²⁶/ 2 X 0.12

T = 68 X 10⁻²⁶s

For semicircular orbit, Time taken would be T/2

T ₓ = 68 X 10⁻²⁶/2 s

T ₓ = 34 X 10⁻²⁶s

Therefore, time taken by each ion to travel the semicircular path through the magnetic field is 34 X 10⁻²⁶s.

4 0
3 years ago
Do you get more flexible by stretching
Alex Ar [27]

Answer:

Yes

Explanation:

By stretching, parts pf your body loosen and become more flexible.

3 0
3 years ago
Read 2 more answers
Compute the mean and maximum velocities for a liquid with a flow rate of 20 L/min in a 1.5-in nominal diameter sanitary pipeline
vlada-n [284]

Answer:

Mean velocity = 0.292 m/s

Maximum velocity = 0.584 m/s

The flow is laminar as Re = 229.2

Explanation:

D = 1.5 inches = 0.0381 m

Q = volumetric flow rate = 20 L/min = 0.000333 m³/s

Q = A × v

A = Cross sectional Area = πD²/4 = π(0.0381)²/4 = 0.00114 m²

v = average velocity

v = Q/A = 0.000333/0.00114 = 0.292 m/s

For flow in circular pipes, maximum velocity = 2 × average velocity = 2 × 0.292 = 0.584 m/s

To check if the flow is laminar or turbulent, we need its Reynolds number

Re = (ρvD)/μ

ρ = 1030 kg/m

v = 0.292 m/s

D = 1.5 inches = 0.0381 m

μ = 50 cP = 0.5 poise = 0.05 Pa.s

Re = (1030 × 0.292 × 0.0381)/0.05 = 229.2

For laminar flow, Re < 2100

For turbulent flow, Re > 4000

And 229.2 < 2100, hence, this flow is laminar.

7 0
3 years ago
Which term identifies the distance between any two adjacent crests on a
ruslelena [56]

Answer:

your answer is wavelength

Explanation:

the the highest service part of a weight is called the crest and the lowest part is the trough the vertical distance between the crest and the trough is the waist height the horizontal disc distance between two adjacent Crest or troughs is known as wavelengths

8 0
4 years ago
Technician A says that failure analysis will assist the technician in determining whether it is more cost effective to replace r
Jobisdone [24]

Answer:

The correct option is;

Technician A

Explanation:

Here we note  failure analysis will assist in determining the cause of failure and as such to determine the cost effectiveness of a repair or a replacement.

However, a warranty is a legal contract between the buyer of the engine and the manufacturer for the manufacturer to either repair the engine or compensate the the customer for all failures that occur within the period of the warranty. Therefore, technician B is not correct as he says the manufacturer may request the engine for analysis on why it failed which is not the same as the basis of a warranty.

6 0
3 years ago
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