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Brilliant_brown [7]
2 years ago
13

Set the radius to 2.0 m and the velocity to 1.0 m/s. Keeping the radius the same, record the magnitude of centripetal accelerati

on for each given velocity. Include units.
Physics
1 answer:
jek_recluse [69]2 years ago
5 0

Answer:

a=4\ m/s^2

Explanation:

Given that,

Radius, r = 2 m

Velocity, v = 1 m/s

We need to find the magnitude of the centripetal acceleration. The formula for the centripetal acceleration is given by :

a=\dfrac{v^2}{r}\\\\a=\dfrac{(2)^2}{1}\\\\=4\ m/s^2

So, the magnitude of centripetal acceleration is 4\ m/s^2.

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Answer:

Magnetic fields exist near a magnet, farther away from a magnet, and within a magnet.

So, the answer is D. All of the above.

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3 years ago
Linus builds an electrical circuit with a battery and with wires that carry the current. As the battery weakens, the current als
pantera1 [17]

Answer:

The field gets weaker

Explanation:

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3 years ago
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Which of the following processes DOES NOT occur during the convective transfer of heat within a container of air? Group of answe
vovangra [49]

The volume of a warmed part of the air is reduced and its density increases.

Explanation:

In a convective form of heat transfer, the volume of a warmed part of air is not reduced and its density does not increase.

During convection, heat causes the warm part of the air to expand and its volume increases. When volume increases, density is reduced.

  • Convection is a form of heat transfer that involves the actual movement of particles of the medium.
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7 0
3 years ago
The total mass of an object can be assumed to be focused at one point, which is called its center of _______. A. force B. veloci
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C.) <span>The total mass of an object can be assumed to be focused at one point, which is called its center of "Mass"

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4 0
3 years ago
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Two 0.2304 cm x 0.2304 cm square aluminum electrodes, spaced 0.5974 mm apart are connected to a 61 V battery. What is the charge
Arisa [49]

Answer:

The charge on each plate is 0.0048 nC

Explanation:

for the distance between the plates d and given the area of plates, A, and ε = 8.85×10^-12 C^2/N.m^2, the capacitance of the plates is given by:

C = (A×ε)/d

   =[(0.2304×10^-2)(0.2304×10^-2)×(8.85×10^-12))/(0.5974×10^-3)

   = 7.86×10^-14 F

then if the plates are connected to a battery of voltage V = 61 V, the charge on the plates is given by:

q = C×V

   = (7.86×10^-14)×(61)

   = 4.80×10^-14 C

   ≈ 0.0048 nC

Therefore, the charge on each plate is 0.0048 nC.

3 0
3 years ago
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