Answer:
A. The potential energy of the positively charge proton from 5v to 7.5v will increase because in an electric field work is done on the proton to move it to a point of higher potential
B. when an electron is moved from 7.5v to 5v it loses potential energy due to the charges lost so as to bring it to a point of lower potential
Explanation:
Answer:
1.5F
Explanation:
Using
E= F/q
Where F= force
E= electric field
q=charge
F= Eq
So if qis tripled and E is halved we have
F= (E/2)3q
F= 1.5Eq=>> 1.5F
Precisely around 1,800 miles below.
I believe the answer is
A. Neutrons attracting to protons
Answer:
12.0 Volt
Explanation:
Step 1: Given data
Resistance of the ohmic dipole (R): 100 Ohm
Intensity of current (I): 120 mA (0.120 A)
Step 2: Calculate the voltage (V) across this chemical dipole
To calculate the voltage across the ohmic dipole, we will use Ohm's law.
I = V/R
V = I × R
V = 0.120 A × 100 Ohm = 12.0 V