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olchik [2.2K]
3 years ago
15

Ask Your Teacher In Example 24.6, we found that the electric field of a charged disk approaches that of a charged particle for d

istances y that are large compared to R, the radius of the disk. To see a numerical instance of this, calculate the magnitude of the electric field a distance y = 2.8 m from a disk of radius R = 2.8 cm that has a total charge of 6.5 µC using the exact formula as follows. (Enter your answer to at least one decimal place.)

Physics
1 answer:
Ulleksa [173]3 years ago
8 0

Answer: E = 7394.6N/C

Explanation:

Please find the attached file for the solution

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Answer:

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Explanation:

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What will be the force if the particle's charge is tripled and the electric field strength is halved? Give your answer in terms
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Answer:

1.5F

Explanation:

Using

E= F/q

Where F= force

E= electric field

q=charge

F= Eq

So if qis tripled and E is halved we have

F= (E/2)3q

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I believe the answer is
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An ohmic dipole of resistance 100 ohm is crossed by a current of intensity 120 ma. Calculates the voltage across this chemical d
Sedaia [141]

Answer:

12.0 Volt

Explanation:

Step 1: Given data

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Intensity of current (I): 120 mA (0.120 A)

Step 2: Calculate the voltage (V) across this chemical dipole

To calculate the voltage across the ohmic dipole, we will use Ohm's law.

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4 0
3 years ago
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