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Triss [41]
4 years ago
12

A wave with a frequency of 0.5 Hz and a speed of 10 m\s has a wavelength of..

Physics
1 answer:
aniked [119]4 years ago
3 0
Wavelength = (speed) divided by (frequency) = 10/0.5 = <span>20 </span>
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Which statement describes between a cup if cold water and a cup of boiling water
marishachu [46]
The thermal energy keeps these two changing their temperature over time. 

The surrounding temperature (environment) clearly effects the cold water AND the boiling water. 

Eventually, both would reach an equilibrium in temperature. <span />
4 0
3 years ago
A 750 watt hairdryer is used for 60 seconds. how many joules of energy are used?
daser333 [38]
We know, Power = Energy / time
Here, P = 750 Watt
t = 60 sec

Substitute their values, 
750 = E / 60
E = 750 * 60
E = 45,000 J

In short, Your Answer would be 45,000 Joules

Hope this helps!
4 0
4 years ago
Read 2 more answers
A car tire has a pressure of 325 kPa when the temperature is 10 C. If the temperature of the tire rises to 50 C and its pressure
MAXImum [283]
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3 0
4 years ago
If the resistance through the fat is 3 times that through the muscle, how much of the total current goes through the fat in term
lapo4ka [179]

Answer:

it A i think

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Explanation:

8 0
2 years ago
Before 1960, people believed that the maximum attainable coefficient of static friction for an automobile tire on a roadway was
Eduardwww [97]

Answer:

4.18

Explanation:

Givens  

The car's initial velocity  v_{i}= 0 and covering a distance Δx = 1/4 mi = 402.336 m in a time interval t = 4.43 s.  

Knowns

We know that the maximum static friction force is given by:

f_{s_max} =μ_s*n                         (1)

Where μ_s is the coefficient of static friction and n is the normal force.  

Calculations  

(a) First, we calculate the acceleration needed to achieve this goal by substituting the given values into a proper kinematic equation as follows:

Δx=v_{i} +\frac{1}{2} at^2

a=41 m/s

This is the acceleration provided by the engine. Applying Newton's second law on the car, so in equilibrium, when the car is about to move, we find that:  

f_{y}=n-mg=0\\ n=mg\\f_{x}=F-f_{s,max} =0\\ f_{s,max}=F=ma\\

Substituting (3) into (1), we get:

f_{s,max}= μ_s*m*g

Equating this equation with (4), we get:

ma=  μ_s*m*g

 μ_s=a/g

      =4.18

3 0
3 years ago
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