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umka21 [38]
8 months ago
10

Classify the disadvantages of unconventional oil and gas extraction as belonging to ei sands mining. ther hydraulic fracturing o

r tar Hydraulic fracturing Tar sands mining Answer Bank local groundwater contamination huge lakes of acidic and toxic wastewater Output outpaces transportation capacity requires heated pipelines for transport destroys habitat and pollutes watersheds corporate rights to oil and gas on private property The breakeven price is S60 per barrel. ye more greenhouse gas emissions Wastewater in injection wells triggers earthquakes.
Physics
1 answer:
Bad White [126]8 months ago
5 0

The disadvantages of unconventional oil and gas extraction as belonging to tar sands mining are as follows:-

Oil and gas extraction:-

  • Local groundwater contamination
  • Corporate rights to oil and gas on private property
  • Waste water in injection wells triggers earthquakes
  • Output outpaces transportations

Tar sand mining:-

  • 20% more greenhouse gas emission
  • Requires heated pipelines for transport
  • Huge lakes of acidic and toxic waste water
  • Destroys habitat and pollutes watersheds

Learn more about gas extraction here:- brainly.com/question/1990340

#SPJ4

Disclaimer:- your question is incomplete, please see below for the complete question.

Classify the disadvantages of unconventional oil and gas extraction as belonging to ei sands mining.

a. ther hydraulic fracturing or tar Hydraulic fracturing Tar sands.

b. mining Answer Bank local groundwater contamination huge lakes of acidic and toxic.

C. wastewater Output outpaces transportation capacity requires heated pipelines for transport destroys habitat and pollutes watersheds corporate rights to oil and gas on private property

D.The breakeven price is S60 per barrel. ye more greenhouse gas emissions Wastewater in injection wells triggers earthquakes

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The index of refraction of silicate flint glass for red light is 1.620 and for violet light is 1.660 . A beam of white light in
chubhunter [2.5K]

Answer:

The angular separation equals 0.35^{o}

Explanation:

We have according to Snell's law

n_{1}sin(\theta _{1})=n_{2}sin(\theta _{2})

\therefore \theta _{2}=sin^{-1}(\frac{n_{1}sin(\theta _{1})}{n_{2}})

Using this equation for both the colors separately we have

\theta _{red}=sin^{-1}(\frac{sin(23.90^{o})}{1.62})\\\\\theta _{red}=14.48^{o}

Similarly for violet light we have

\theta _{violet}=sin^{-1}(\frac{sin(23.90^{o})}{1.660})\\\\\theta _{violet}=14.13^{o}

Thus the angular separation becomes

\Delta \theta =14.48-14.13=0.35^{o}

6 0
3 years ago
Protons, neutrons, electrons, and a nucleus are
tatuchka [14]
It would be Atoms, they’re all made up of these tiny particles
8 0
3 years ago
Solve the problem.
gulaghasi [49]
As the shock waves travel in concentric outward circles from the epicenter, and the diameter is measured 120 miles,
area of a circle =<span>π</span><span>r*r</span>

d=120
<span>r=<span>120/2</span></span><span>r=60</span><span><span>60*60</span>=3600</span><span>3600*π=11309.734</span>
<span>11309.734 square miles</span>
5 0
3 years ago
A mass m attached to a horizontal massless spring with spring constant k, is set into simple harmonic motion. its maximum displa
Lesechka [4]
At the point of maximum displacement (a), the elastic potential energy of the spring is maximum:
U_i= \frac{1}{2} ka^2
while the kinetic energy is zero, because at the maximum displacement the mass is stationary, so its velocity is zero:
K_i =0
And the total energy of the system is
E_i = U_i+K= \frac{1}{2}ka^2

Viceversa, when the mass reaches the equilibrium position, the elastic potential energy is zero because the displacement x is zero:
U_f = 0
while the mass is moving at speed v, and therefore the kinetic energy is
K_f =  \frac{1}{2} mv^2
And the total energy is
E_f = U_f + K_f =  \frac{1}{2} mv^2

For the law of conservation of energy, the total energy must be conserved, therefore E_i = E_f. So we  can write
\frac{1}{2} ka^2 =  \frac{1}{2}mv^2
that we can solve to find an expression for v:
v= \sqrt{ \frac{ka^2}{m} }
6 0
3 years ago
Alan and Monica tested how fertilizer X affected the growth of a plant. Alan and Monica put 100 grams of fertilizer X in pot 1.
BARSIC [14]

Answer:

D.

a control group

Explanation:

In a scientific experiment such as the one above, there is an experimental group and a control group. The experimental group is the group that receives the treatment while the control group does not receive any treatment. The control group helps the researcher to observe if the treatment had any significant effect.

In this case, it will help Alan and Monica to determine if fertilizer X actually had an effect on the plant. Therefore, the pot with o grams of fertilizer in it is the control group.

7 0
2 years ago
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