Answer:
The maximum emf that can be generated around the perimeter of a cell in this field is 
Explanation:
To solve this problem it is necessary to apply the concepts on maximum electromotive force.
For definition we know that

Where,
N= Number of turns of the coil
B = Magnetic field
Angular velocity
A = Cross-sectional Area
Angular velocity according kinematics equations is:



Replacing at the equation our values given we have that




Therefore the maximum emf that can be generated around the perimeter of a cell in this field is 
For circular motion we know that
<span>F=ma=v^2/r </span>
<span>Therefore: </span>
<span>v = sqrt (rma) </span>
<span>Also, for cicular motion: </span>
<span>rev/min. = 60v/(2r*pi) </span>
<span>So your equation is: </span>
<span>rev./min = 60sqrt(rma)/(2pi*r) </span>
<span>For the mass (m) we can just use 1 kg.
</span>
rev./min = 60sqrt(730*1*9.8)/(2pi*730) =60sqrt(7154)/(4584.4)
rev./min = 60sqrt(7154)/(4584.4) =1.11 rev/min
<span>
the answer is </span>1.11 rev/min<span>
</span>
Answer:
model 3
Explanation:
Boron with atomic number 5 will have 3 valence electrons
The gravity is pushing rhe boat down
Yes! you are :) bc you are FORCING the page to turn, and the broom ti sweep