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3 years ago

10

True or False. The Magnitude of the induced voltage in a coil of wire depends on how quickly the magnetic flux through the coil

of wire changes.

2 answers:

marishachu [46]3 years ago

7 0

Answer: yes its true

Explanation:

nmo

EleoNora [17]3 years ago

5 0

Answer:

Yes, its true

Explanation:

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What can cause a production possibilities curve to move to the right?

Bas_tet [7]

Answer:

Option D

a new invention lowers the cost of production

Explanation:

When there is a new invention lowers the cost of production, the production is likely to increase since the time allocated is as previous. Therefore, the curve moves to the right, to indicate a positive direction

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3 years ago

What is the best explanation for why, on average, children playing inside a

Anestetic [448]

Answer:

In a house there is a lot less space so there is no where for the sound to travel, but if you are outside there is a lot more space so therefore, the sound can travel anywhere.

Explanation:

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3 years ago

A mass-spring system has k = 56.8 N/m and m = 0.46 kg.

andriy [413]

Answer:

A. $\omega=11.1121\ rad.s^{-1}$

B. $f=1.7685\ Hz$

C. $T=0.5654\ s$

Explanation:

Given:

spring constant, $k=56.8\ N.m^{-1}$

mass attached, $m=0.46\ kg$

A)

for a spring-mass system the frequency is given as:

$\omega=\sqrt{\frac{k}{m} }$

$\omega=\sqrt{\frac{56.8}{0.46}}$

$\omega=11.1121\ rad.s^{-1}$

B)

frequency is given as:

$f=\frac{\omega}{2\pi}$

$f=\frac{11.1121}{2\pi}$

$f=1.7685\ Hz$

C)

Time period of a simple harmonic motion is given as:

$T=\frac{1}{f}$

$T=0.5654\ s$

7 0

3 years ago

An ion accelerated through a potential difference of 115 V experiences an increase in kinetic energy of 7.37 x 1017 J. Calculate

riadik2000 [5.3K]

Answer: $6.408(10)^{-19} C$

Explanation:

This problem can be solved by the following equation:

$\Delta K=q V$

Where:

$\Delta K=7.37(10)^{-17} J$ is the change in kinetic energy

$V=115 V$ is the electric potential difference

$q$ is the electric charge

Finding $q$ :

$q=\frac{\Delta K}{V}$

$q=\frac{7.37(10)^{-17} J}{115 V}$

Finally:

$q=6.408(10)^{-19} C$

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3 years ago

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3 years ago