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ale4655 [162]
1 year ago
13

How many particles are in 64 grams of Oxygen?

Chemistry
1 answer:
Simora [160]1 year ago
3 0

Answer:

4

Explanation:

oxygen has molar mass of 16 g/mol. 64 grams / 16 g/mol = 4mol

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MA_775_DIABLO [31]

Answer:

Deposition

Explanation:

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It requires work to _____. A. stretch a spring only B. compress a spring only C. stretch or compress a spring
maria [59]

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C.

Explanation:

It requires work to stretch or compress a spring.

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What is one similarity among elements in a group?
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B chemical properties is a right answer
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3 years ago
Upon combustion, a compound containing only carbon and hydrogen produces 2.67 g<img src="https://tex.z-dn.net/?f=CO_%7B2%7D" id=
Hoochie [10]

Answer:

\boxed{\text{CH$_{2}$}}

Explanation:

1. Calculate the mass of each element

\text{Mass of C} = \text{2.67 g } \text{CO}_{2}\times \dfrac{\text{12.01 g C}}{\text{44.01 g }\text{CO}_{2}}= \text{0.7286 g C}\\\\\text{Mass of H} = \text{1.10 g }\text{H$_{2}$O}\times \dfrac{\text{2.016 g H}}{\text{18.02 g } \text{{H$_{2}$O}}} = \text{0.1231 g H}

2. Calculate the moles of each element

\text{Moles of C = 0.7286 g C}\times\dfrac{\text{1 mol C}}{\text{12.01 g C }} = \text{0.060 67 mol C}\\\\\text{Moles of H = 0.1231 g H} \times \dfrac{\text{1 mol H}}{\text{1.008 g H}} = \text{0.1221 mol H}

3. Calculate the molar ratios

Divide all moles by the smallest number of moles.

\text{C: } \dfrac{0.06067}{0.06067}= 1\\\\\text{H: } \dfrac{0.1221}{0.06067} = 2.015

4. Round the ratios to the nearest integer

C:H = 1:2

5. Write the empirical formula

The empirical formula is \boxed{\text{CH$_{2}$}}

8 0
3 years ago
What is the gram formula mass of Ca3(PO4)2
Georgia [21]
Mass Molar of Ca_{3} (PO_4)_2
Ca = 3*40 = 120 amu
P = 2*31= 62 amu
O = (16*4)*2 = 64*2 = 128 amu
--------------------------------------
Mass Molar of Ca_{3} (PO_4)_2 = 120 + 62 + 128 = 310 g/mol

Therefore: <span>What is the gram formula mass of Ca3(PO4)2 ?
</span>Answer: 310 grams
6 0
3 years ago
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