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marin [14]
3 years ago
12

How many moles of hydrogen atoms are there in 1.25 x 1025 molecules of ethane? (C2H6)

Chemistry
1 answer:
krek1111 [17]3 years ago
7 0

Answer:

124.56 moles of Hydrogen atoms.

Explanation:

We'll begin by calculating the number of moles of ethane that contains 1.25×10²⁵ molecules. This can be obtained as follow:

From Avogadro's hypothesis, 1 mole of any substance contains 6.02x10²³ molecules. This implies that 1 mole of ethane also contains 6.02x10²³ molecules.

Thus, 6.02x10²³ molecules are present in 1 mole of ethane.

Therefore, 1.25×10²⁵ molecules are present in = 1.25×10²⁵/6.02x10²³ = 20.76

Therefore, 20.76 moles of ethane contains 1.25×10²⁵ molecules.

Finally, we shall determine the number of mole of Hydrogen in 20.76 moles of ethane. This can be obtained as follow:

Ethane has formula as C2H6.

From the formula, 1 mole of ethane, C2H6 contains 6 moles of Hydrogen atoms.

Therefore, 20.76 moles of ethane will contain = 20.76 × 6 = 124.56 moles of Hydrogen atoms.

Therefore, 1.25×10²⁵ molecules of ethane contains 124.56 moles of Hydrogen atoms.

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3 0
3 years ago
What expression approximates the volume of O2 consumed, measure at STP, when 55 g of Al reacts completely with excess O2?2 Al(s)
Genrish500 [490]

Answer:

34.28 L ( 1.5*22.4 L)

Explanation:

Calculation of the moles of aluminum as:-

Mass = 55 g

Molar mass of aluminum = 26.981539 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{55\ g}{26.981539\ g/mol}

Moles= 2.0384\ mol

According to the reaction:-

4Al+3O_2\rightarrow 2Al_2O_3

4 moles of aluminum react with 3 moles of oxygen gas

1 mole of aluminum react with \frac{3}{4} moles of oxygen gas

2.0384 moles of aluminum react with \frac{3}{4}\times 2.0384 moles of oxygen gas

Moles of oxygen gas = 1.5288 moles

At STP,  

Pressure = 1 atm  

Temperature = 273.15 K

Using ideal gas equation as:

PV=nRT

where,

P is the pressure

V is the volume

n is the number of moles

T is the temperature

R is Gas constant having value = 0.0821 L.atm/K.mol

Applying the equation as:

1 atm × V = 1.5288 mol × 0.0821 L.atm/K.mol × 273.15 K

⇒V = 34.28 L ( 1.5*22.4 L)

7 0
3 years ago
Please select the most appropriate answer for the blank: Entropy change is defined only along the path of a(n) ___________ proce
Whitepunk [10]

Entropy change is defined only along the path of an internally reversible process path.

<h3><u>What is Entropy Change </u>?</h3>
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  • Entropy Change is a phenomena that measures how disorder or randomness have changed inside a thermodynamic system.
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  • Entropy is a state function, hence it is independent of the direction that the thermodynamic process takes.
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8 0
2 years ago
In the chemical equation: NO(g) + ½Cl2(g) → NOCl(g) How many moles of NOCl(g) are in the balanced chemical equation? fill in bla
Mrrafil [7]

Answer:

1

Explanation:

The numbers in front of the formulas (the coefficients) tell you how many moles of a substance are involved in a reaction.

If no coefficient is shown, we assume it is 1.

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4 0
4 years ago
Read 2 more answers
Question 43 please. i’m not sure if i got the right answer
hram777 [196]

a) The reaction is exothermic since the overall enthalpy change is negative. this means that the system has lost energy to the environment, namely, the apparatus and due to drought.

b) We first calculate the number of moles in 3.55 grams of magnesium.

number of moles= mass/ atomic mass

                            =3.55/24

                            =0.1479 moles(to 4sf)

now, if 2 moles of magnesium give -1204kJ

        How much energy is given by 0.1479 moles

       = (0.1479×-1204kJ)

        =-89.0358kJ (don't forget the negative sign)

c) two molesof MgO produces -1204kJ of energy

then -234kJ will be produced by

=(-234kJ×2moles)/1204kJ

=0.3887moles

one mole of MgO weighs 24+16=40

therefore the mass produced is 0.3887moles×40=15.548grams

(d) we first find the number of moles of MgO in 40.3 grams

number of moles=mass/RFM

=40.3g/40= 1.0075moles

if 2 moles of MgO give 1204 kJ then decomposing 1.0075 moles requires

(1.0075 moles×1204kJ)/2=606.515kJ

4 0
3 years ago
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