The concentration of solids is constant and usually taken equal to unity ,therefore it does not appear in the equilibrium constant ,so adding or removing solid has no effect. So According to Le Chatelet's Principle the amount of solid reactant or product present does not have an impact on the equilibrium
What is Le Chatelet's Principle ?
The position of the equilibrium in a chemical reaction can be predicted with the aid of Le Chatelet's Principle in response to changes in temperature, concentration, or pressure. This is crucial, especially for industrial applications where it's crucial to predict and maximize yields.
According to Le Châtelet's principle, if a dynamic equilibrium is upset by changing the conditions, the equilibrium position will move to compensate for the change and restore the equilibrium.
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Question:
A) 12
B) 29
C) 2.1 × 10⁻²
D) 8.7 × 10⁻²
E) 47
Answer:
The correct option is;
E) 47
Explanation:
Kc, which is the equilibrium constant of a chemical reaction is derived by finding the ratio between the product of the equilibrium concentration of the product raised to their respective coefficients to the product of the equilibrium concentration of the reactants also raised to their respective coefficients.
Here we have;
[H₂] = 0.14 M
[Cl₂] = 0.39 M
[HCl] = 1.6
The reaction is given as follows;
H₂ (g) + Cl₂ (g) ⇄ 2HCl (g)
The formula for Kc is given as follows;
![Kc = \frac{[HCl]^2}{[H_2][Cl_2]} = \frac{1.6^2}{0.14 \times 0.39} = 46.886](https://tex.z-dn.net/?f=Kc%20%3D%20%5Cfrac%7B%5BHCl%5D%5E2%7D%7B%5BH_2%5D%5BCl_2%5D%7D%20%3D%20%5Cfrac%7B1.6%5E2%7D%7B0.14%20%5Ctimes%200.39%7D%20%20%3D%2046.886)
Therefore, the Kc for the reaction is approximately equal to 47.
Answer:
I think its iron(II) oxide
Explanation:
The substance is black but when it's mixed with water it turns green solution so when mixed with sodium Hydroxide it turns green
Answer is: <span>C.)It will be closer to the mass of Vi–193.
</span><span>Average atomic mass of vitellium =
Ar(Vi-188) </span>· ω(Vi-188) + Ar(Vi-191) · ω(Vi-191) + Ar(Vu-193) · ω(Vi-193).
Average atomic mass of vitellium =
187.9122 amu · 0,10861 + 190.9047 amu · 0,12428 + 192.8938 amu · 0,76711.
Average atomic mass of vitellium = 20,409 + 23,725 + 147,970.
Average atomic mass of vitellium = 192,104.
