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2 years ago

8

On average, a family living on Pine Street spends $238.79 a year on school supplies. About how much does one of these families s

pend each month on school supplies? 12 months=1 year
A. $12
B. $20
C. $24
D. $36

1 answer:

maks197457 [2]2 years ago

5 0

Must be C.$24 but I'm not 100% sure.

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Several paint mixtures are made by mixing blue paint and white paint. Paint Colors Blue Paint White Paint Mixture A 5 cups 12 cu

Nesterboy [21]

Answer:

The mixture C is the correct option

Step-by-step explanation:

According to the given scenario, the calculation is as follows:

For Mixture A

Blue Paint - 5 cups

White Paint - 12 cups

The ratio between them is 5:12

For Mixture B

Blue Paint - 6 cups

White Paint - 6 cups

The ratio between them is 6:6 = 12:12

It came by multiply the numerator and denominator by 12

For Mixture C

Blue Paint - 4 cups

White Paint - 12 cups

The ratio between them is 4:12

For Mixture D

Blue Paint - 5 cups

White Paint - 6 cups

The ratio between them is 5:6 = 10:12

It came by multiply the numerator and denominator by 12

As it can be seen that in all four mixtures the denominator is the same so for calculating the lowest ratio we have to see the small value in the numerator

As it can be seen that there is a small value of 4

hence, the mixture C is the correct option

5 0

2 years ago

Read 2 more answers

What is the area of a regular hexagon with a side length of 6 yd? Enter your answer in the box. Round only your final answer to

tatuchka [14]

Your answer would be 93.53

5 0

3 years ago

Read 2 more answers

–9(w + 585) = –360 w = ______

vekshin1

Answer:

w = 15

Step-by-step explanation:

-9(w + 585) = -360w

-9w -5265 = -360w

351w = 5265

w=15

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3 years ago

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a circle has a center (3,5) and a diameter AB. The coordinates of A are (-4,6). what are the coordinates of B?

Kruka [31]

Find the length of the radius.

$r= \sqrt{(3-(-4))^2+(5-6)^2}
\\r = \sqrt{7^2+(-1)^2}
\\r= \sqrt{50} 
\\ r=5 \sqrt{2}$

Find the length of the diameter.

d = 2r = 2 × 5√2 = 10√2

Point B must lie on a line AC, where C is a center of a circle.
Find equation of line AC.
A(–4, 6), C(3, 5)

$y-y_1= \frac{y_2-y_1}{x_2-x_1}(x-x_1)
\\y-6= \frac{5-6}{3-(-4)} (x-(-4))
\\y-6=- \frac{1}{7} (x+4)
\\7y-42=-x-4
\\x+7y-38=0$

The distance from B(x, y) to C(3, 5) is 5√2.
$\sqrt{(x-3)^2+(y-5)^2}=5 \sqrt{2} 
 \\(x-3)^2+(y-5)^2=(5 \sqrt{2})^2 
\\(x-3)^2+(y-5)^2=50$

Solve system of equations.
$x+7y-38=0
\\(x-3)^2+(y-5)^2=50
\\
\\x=38-7y
\\(38-7y-3)^2+(y-5)^2=50
\\(35-7y)^2+(y-5)^2=50
\\1225-490y+49y^2+y^2-10y+25-50=0
\\50y^2-500y+1200=0
\\y^2-10y+24=0
\\y^2-6y-4y+24=0
\\y(y-6)-4(y-6)=0 \\(y-6)(y-4)=0 \\y_1=6,y_2=4
$

$x_1=38-7y_1=38-7 \times 6 = 38-42=-4
\\x_2=38-7y_2=38-7 \times 4 = 38-28=10
$

Point B could have coordinates
$\\
\\(x_1,y_1)=(-4,6),(x_2,y_2)=(10,4)
$

But (–4, 6) are the coordinates of point A.
Therefore, point B has coordinates (10,4).

8 0

3 years ago

Secants ⎯⎯⎯⎯⎯⎯⎯⎯ and ⎯⎯⎯⎯⎯⎯⎯⎯⎯ intersect in the exterior of a circle. The measures of ⏜ and ⏜ are 112.54° and 26.32°, respective

Veseljchak [2.6K]

Answer:

C. 43.11°

Step-by-step explanation:

The formula to use in finding m<BCD = ½ the difference of the intercepted arcs AE and BD

Thus:

m<BCD = ½(AE - BD)

m<BCD = ½(112.54 - 26.32)

m<BCD = ½(86.22)

m<BCD = 43.11°

5 0

2 years ago