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ch4aika [34]
2 years ago
6

Simplify 425xy⁴/25xy²

Mathematics
1 answer:
beks73 [17]2 years ago
3 0

We have the expression

\frac{425xy^4}{25xy^2}

We can already simplify x because it's both on the numerator and denominator

\frac{425y^4}{25y^2}

Now we can simplify 425/25 = 17

\frac{17y^4}{y^2}

Remember that

\frac{a^n}{a^m}=a^{n-m}

Then

17y^{4-2}=17y^2

The final result is

17y^2

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Answer:

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Step-by-step explanation:

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Find the circumference of a circle with diameter, d = 23cm.<br>Give your answer in terms of pi​
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perimeter =

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3 years ago
Give an example of a function with both a removable and a non-removable discontinuity.
navik [9.2K]

Answer:

(x+5)(x-3) / (x+5)(x+1)

Step-by-step explanation:

A removeable discontinuity is always found in the denominator of a rational function and is one that can be reduced away with an identical term in the numerator.  It is still, however, a problem because it causes the denominator to equal 0 if filled in with the necessary value of x.  In my function above, the terms (x + 5) in the numerator and denominator can cancel each other out, leaving a hole in your graph at -5 since x doesn't exist at -5, but the x + 1 doesn't have anything to cancel out with, so this will present as a vertical asymptote in your graph at x = -1, a nonremoveable discontinuity.

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Use the discriminant to describe the roots of each equation. Then select the best description. 2x2 + 7x + 6 = 0 double root real
arlik [135]

So the equation to find the discriminant is √(b^2 - 4ac), with a = x^2 coefficient, b = x coefficient, and c = constant. Using our equation above, we can solve for it as such:

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