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denis23 [38]
1 year ago
5

What is the slope of a line perpendicular to the line whose equation is 3x + 6y = –72. Fully reduced

Mathematics
1 answer:
VARVARA [1.3K]1 year ago
5 0

The slope of the line is 2 for the equation that is perpendicular.

Slope of the line:

Slope of the line refers the change in y coordinate with respect to the change in x coordinate.

Given,

Here we have the equation 3x + 6y = - 72 that is perpendicular to the line.

Now, we need to find the slope of the line from it.

First we have to convert the given equation of line into standard form,

Then we get,

3x + 6y + 72 = 0

Now we know that the slope of the line for this type of equation is,

m = -a/b

Whlie we compare the equation with the standard form ax + by + c = 0,

Then we get the value of a = 3 and b = 6

Therefore, the slope of the line is

m1 = -3/6

m1 =-1/2

Here we need to find the slope of a line which is perpendicular to the given line.

Through the definition we know that product of two perpendicular line is -1.

So,

m1 x m2 = -1

(-1/2) x m2 = -1

m2 = 2

Therefore, the slope of perpendicular line is 2

To know more about Slope of the line here.

brainly.com/question/16180119

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Answer:

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Answer:

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Step-by-step explanation:

Circumference is the perimeter of a circle. It can be found using the formula:

c= \pi d

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The formula can be rewritten as:

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madreJ [45]
#13 would be 100%.
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jek_recluse [69]

Answer:

1. wire is approx. 143.96 ft

2. pole is approx. 106.55 ft

Step-by-step explanation:

Mapping the information on the SOHCAHTOA picture below:

Φ = 46

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adjacent side = 100

CAH is most suitable:

cos 46° = 100/wire => wire = 100/cos 46 ≈ 143.96

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TOA is most suitable:

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