Question

What is the slope of a line perpendicular to the line whose equation is 3x + 6y = –72. Fully reduced

Answer 1

The slope of the line is 2 for the equation that is perpendicular.

Slope of the line:

Slope of the line refers the change in y coordinate with respect to the change in x coordinate.

Given,

Here we have the equation 3x + 6y = - 72 that is perpendicular to the line.

Now, we need to find the slope of the line from it.

First we have to convert the given equation of line into standard form,

Then we get,

3x + 6y + 72 = 0

Now we know that the slope of the line for this type of equation is,

m = -a/b

Whlie we compare the equation with the standard form ax + by + c = 0,

Then we get the value of a = 3 and b = 6

Therefore, the slope of the line is

m1 = -3/6

m1 =-1/2

Here we need to find the slope of a line which is perpendicular to the given line.

Through the definition we know that product of two perpendicular line is -1.

So,

m1 x m2 = -1

(-1/2) x m2 = -1

m2 = 2

Therefore, the slope of perpendicular line is 2

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