9 + 1.34 + 1 2 (3.50 +1.74)
Step 1: add what is inside the parenthesis
9 + 1.34 + 1 2 (5.24)
Step 2: multiply what is inside the parenthesis by 12.
9 + 1.34 + 62.88
Step 3: Add all the numbers
73.22
answer
9 + 1.34 + 1 2 (3.50 +1.74) = 73.22
Answer:
is that even a real equation?
Answer:
Step-by-step explanation:
these are two different questions .
first i solve first
position of submarine= -250/3 meters below see level
height descended=120 % of 250/3=120/100 ×(250/3)=300,00/300=100 m
new location=-250/3+(-100)=-650/3 below see level.
2nd question
position of submarine=-250 2/3=-752/3 m below see level
height descended=120 5/8=965/8 m =-965/8 m below see level
new positin=-752/3+(-965/8)=-(6016+2895)/24=-8911/24=-371 7/24m below sesa level.
There are 14 sections with a score higher than 5. And there 20 in total. The probability is:
P(t) = P₀ e^(kt)
<span>Where P₀ is the initial population, </span>
<span>P(t) is the population after "t" time. </span>
<span>t is your rate (can be hours, days, years, etc. in this case, hours) </span>
<span>k is the growth constant for this particular problem. </span>
<span>So using the information given, solve for k: </span>
<span>P₀ = 2000 </span>
<span>P(4) = 2600 </span>
<span>P(t) = P₀ e^(kt) </span>
<span>2600 = 2000e^(k * 4) </span>
<span>1.3 = e^(4k) </span>
<span>Natural log of both sides: </span>
<span>ln(1.3) = 4k </span>
<span>k = ln(1.3) / 4 </span>
<span>Now that we have a value for "k", use that, the same P₀, then solve for P(17): </span>
<span>P(t) = P₀ e^(kt) </span>
<span>P(17) = 2000 e^(17ln(1.3) / 4) </span>
<span>Using a calculator to get ln(1.3) then to simplify from there, we get: </span>
<span>P(17) ≈ 2000 e^(17 * 0.262364 / 4) </span>
<span>P(17) ≈ 2000 e^(4.460188 / 4) </span>
<span>P(17) ≈ 2000 e^(1.115047) </span>
<span>P(17) ≈ 2000 * 3.0497 </span>
<span>P(17) ≈ 6099.4 </span>
<span>Rounded to the nearest unit: </span>
<span>P(17) ≈ 6099 bacteria hope i could help =)))</span>
