Question

Suppose there are 8 blue, 4 green, 11 yellow, and 7 red buttons in a bag. If you randomly pick out one button, what is the probability it is red or green?

Answer 1

11/29 i believe. Cuz you add them all together and get 29 and then red and green added together is 11 

Answer 2

Answer: $\dfrac{11}{30}$

Step-by-step explanation:

Given : The number of red buttons = 7

The number of green buttons = 4

The total number of buttons = 8+4+11+7= 30

The probability of picking a red button is given by :-

$P(R)=\dfrac{\text{Red buttons}}{\text{Total buttons}}\\\\=\dfrac{7}{30}$

The probability of picking a green button is given by :-

$P(G)=\dfrac{\text{Green buttons}}{\text{Total buttons}}\\\\=\dfrac{4}{30}$

Since both the events are independent then the the probability it is red or green is given by :-

$P(R\cup G)=P(G)+P(R)\\\\=\dfrac{4}{30}+\dfrac{7}{30}=\dfrac{11}{30}$