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1 year ago

On the line below, write the two places you can control tab settings.

Computers and Technology

1 answer:

nikklg [1K]1 year ago

4 0

The two places you can control tab settings are the ruler and in the dialog box.

<h3>What are setting tabs?</h3>

The Ctrl + Tab is one that is often referred to as Control Tab and C-tab or the Ctrl+Tab.

It is known to be a keyboard shortcut that is said to be most often used to chose between open tabs in a browser.

Note that the settings Tabs are said to be a kind of paragraph-formatting tool that is often used to align text.

Hence, The two places you can control tab settings are the ruler and in the dialog box.

Learn more about control tab settings from

brainly.com/question/11509892

#SPJ1

See full question below

Where can’t you control tab settings? Check all the apply

On a ruler

In a dialog box

In the mini toolbar

In the paste special options

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1. provide at least 3 properties and 3 methods of the object computer.

ValentinkaMS [17]

Answer:

The answers to these questions are given below in the explanation section.

Explanation:

The following are 3 properties and 3 methods of the object computer.

Solution

Properties:

computer name;
computer model;
computer color;
computer manufacturer

Methods:

Turn on/off
Do Wordprocessing
Connect Keyboard/Mouse
Charging
Play sound

The following are 3 properties and 3 methods of the object computer.

Properties:

Car Model;
Car Manufacturer;
Car Color

Methods:

Car Run (Speed)
Change Gear
Open/Close Door
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3 years ago

Convert 12 bits to bytes

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Answer:

1.5 bytes

Explanation:

I byte = 8 bit ....

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2 years ago

What is a fire wall and how does it work

Ostrovityanka [42]

Answer:

a firewall is a network security system that monitors and controls incoming and outgoing network traffic based on predetermined security rules

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3 years ago

IF YOU COULD CREATE A SOCIAL NETWORK:, what would it be like? What would make it so special about the others? (If you want you c

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3 years ago

Oxnard Casualty wants to ensure that their e-mail server has 99.98 percent reliability. They will use several independent server

sattari [20]

Answer:

The smallest number of servers required is 3 servers

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Explanation:

Given

$Reliability = 99.98\%$

$Individual Servers = 95\%$

Required

Minimum number of servers needed

Let p represent the probability that a server is reliable and the probability that it wont be reliable be represented with q

Such that

$p = 95\%\\$

It should be noted that probabilities always add up to 1;

So,

$p + q = 1$ '

Subtract p from both sides

$p - p + q = 1 - p$

$q = 1 - p$

Substitute $p = 95\%\\$

$q = 1 - 95\%$

Convert % to fraction

$q = 1 - \frac{95}{100}$

Convert fraction to decimal

$q = 1 - 0.95$

$q = 0.05$

------------------------------------------------------------------------------------------------

<em>To get an expression for one server</em>

The probabilities of 1 servers having 99.98% reliability is as follows;

$p = 99.98\%$

Recall that probabilities always add up to 1;

So,

$p + q = 1$

Subtract q from both sides

$p + q - q = 1 - q$

$p = 1 - q$

So,

$p = 1 - q = 99.98\%$

$1 - q = 99.98\%$

Let the number of servers be represented with n

The above expression becomes

$1 - q^n = 99.98\%$

Convert percent to fraction

$1 - q^n = \frac{9998}{10000}$

Convert fraction to decimal

$1 - q^n = 0.9998$

Add $q^n$ to both sides

$1 - q^n + q^n= 0.9998 + q^n$

$1 = 0.9998 + q^n$

Subtract 0.9998 from both sides

$1 - 0.9998 = 0.9998 - 0.9998 + q^n$

$1 - 0.9998 = q^n$

$0.0002 = q^n$

Recall that $q = 0.05$

So, the expression becomes

$0.0002 = 0.05^n$

Take Log of both sides

$Log(0.0002) = Log(0.05^n)$

From laws of logarithm $Loga^b = bLoga$

So,

$Log(0.0002) = Log(0.05^n)$ becomes

$Log(0.0002) = nLog(0.05)$

Divide both sides by $Log0.05$

$\frac{Log(0.0002)}{Log(0.05)} = \frac{nLog(0.05)}{Log(0.05)}$

$\frac{Log(0.0002)}{Log(0.05)} = n$

$n = \frac{Log(0.0002)}{Log(0.05)}$

$n = \frac{-3.69897000434}{-1.30102999566}$

$n = 2.84310893421$

$n = 3 (Approximated)$

<em>Hence, the smallest number of servers required is 3 servers</em>

6 0

3 years ago