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Fiesta28 [93]
1 year ago
10

The properties of an unknown substance can be compared to the properties of a known substance to identify the unknown substance.

Chemistry
1 answer:
Nitella [24]1 year ago
5 0

Answer:  Physical properties are those that can be determined or measured without changing the composition or identity of the substance. These properties include color, odor, taste, density, melting point, boiling point, conductivity, and hardness.

Explaination:

By using Physical properties unknown substance can be identified as it involves determination of a substance with out changing their composition or property include color, odor, taste, density, melting point etc.

What are the difference between physical and chemical property ?

Chemical properties can be observed or measured when a substance undergoes any type of changes chemically while Physical properties can be observed without changing anything.

In chemical property, chemical reaction is conducted to show the property of the substance while in physical property No chemical reaction occur.

Chemical properties related to chemical bonds while Physical properties do not have such a relationship.

Chemical properties include radioactivity, toxicity, flammability, heat of combustion,  etc. while physical properties include Molecular weight, boiling point, melting point, freezing point, volume, mass, length, density shape, solubility, etc.

<em>If this helped you please consider marking this as the Brainliest Answer, if i make it to 10, I can be promoted to an expert. How? - Once you get more than 1 answer of a question. A message is shown above each answer that is "Mark as brainiest". Click on the option to mark it the best answer. Thank you!</em>

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Why is the formation of water a synthesis reaction?
lisabon 2012 [21]

Explanation:

A synthesis reaction: It is defined as a kind of reaction where one and more than one reactant attached and creates an individual product.

The formation of the water is an example of a synthesis reaction because here more than one reactants combine and create a single product (water). Water formation occurs when 2 hydrogens and an oxygen share electrons through covalent bonds.

2H + O ----> H2O.

7 0
3 years ago
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Blizzard [7]
1. Option A. Temperature and Salinity
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8 0
3 years ago
8. The time period of artificial satellite in a circular orbit of radius R is T. The radius of the orbit in which time period is
Elena-2011 [213]

Explanation:

It is given that,

The time period of artificial satellite in a circular orbit of radius R is T. The relation between the time period and the radius is given by :

T^2\propto R^3

The radius of the orbit in which time period is 8T is R'. So, the relation is given by :

(\dfrac{T}{T'})^2=(\dfrac{R}{R'})^3

(\dfrac{T}{8T})^2=(\dfrac{R}{R'})^3  

\dfrac{1}{64}=(\dfrac{R}{R'})^3

R'=4\times R

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4 0
3 years ago
calculate the volume occupied by 10g of propane gas, under normal conditions of temperature and pressure
andriy [413]

Answer:

5.5 L

Explanation:

First we <u>convert 10 g of propane gas</u> (C₃H₈) to moles, using its <em>molar mass</em>:

  • 10 g ÷ 44 g/mol = 0.23 mol

Then we <u>use the PV=nRT formula</u>, where:

  • P = 1 atm & T = 293 K (This are normal conditions of T and P)
  • n = 0.23 mol
  • R = 0.082 atm·L·mol⁻¹·K⁻¹
  • V = ?

1 atm * V = 0.23 mol * 0.082 atm·L·mol⁻¹·K⁻¹ * 293 K

  • V = 5.5 L
3 0
3 years ago
Use the ideal gas law to calculate the concentrations of nitrogen and oxygen present in air at a pressure of 1.0 atm and a tempe
notka56 [123]

Answer:

[N₂] = 0.032 M

[O₂] = 0.0086 M

Explanation:

Ideal Gas Law → P . V = n .  R . T

We assume that the mixture of air occupies a volume of 1 L

78% N₂ → Mole fraction of N₂ = 0.78

21% O₂  → Mole fraction of O₂ = 0.21

1% another gases  → Mole fraction of another gases = 0.01

In a mixture, the total pressure of the system refers to total moles of the mixture

1 atm . 1L = n . 0.082L.atm/mol.K . 298K

n = 1 L.atm / 0.082L.atm/mol.K . 298K → 0.0409 moles

We apply the mole fraction to determine the moles

N₂ moles / Total moles = 0.78 → 0.78 . 0.0409 mol = 0.032 moles N₂

O₂ moles / Total moles = 0.21 → 0.21 . 0.0409 mol = 0.0086 moles O₂

4 0
3 years ago
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