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Pavlova-9 [17]
11 months ago
6

at the center of the neutral metal block, what is the direction of the electric field contributed by the charge in and on the me

tal block only?
Physics
1 answer:
elena-14-01-66 [18.8K]11 months ago
4 0

The direction of electric field by the charge in and on the metal block will be along the direction line 5 as given in question.

<h3>How to determine electric field direction in a metal block?</h3>

The charge always remain on outer surface of metal and inside the metal block, the net electric field is zero. But due to dipole there is an electric field at the center of metal block i.e. at point R along direction line 1.

Now, to make make the net electric field zero at center, the electric field by the charge in and on the metal block must be equal in magnitude to that of electric field due to dipole at point R and in opposite direction to that of the net electric field at at R due to dipole.

The electric field by the charge in and on the metal block will be making 180° angle to the  electric field due to dipole at point R.

Hence the direction of electric field by the charge in and on the metal block will be along the direction line 5 as given in question.

To know more about electric field, click on brainly.com/question/11509296

#SPJ4

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In an experiment, a variable, position-dependent force FC) is exerted on a block of mass 1.0 kg that is moving on a horizontal s
marshall27 [118]

Answer:

C) The function F(x) for 0 < x < 5, the block's initial velocity, and the value of Fr.

Explanation:

Yo want to prove the following equation:

W_N=\Delta K\\\\

That is, the net force exerted on an object is equal to the change in the kinetic energy of the object.

The previous equation is also equal to:

F(x)x-F_f=\frac{1}{2}m(v_f^2-v_o^2)    (1)

m: mass of the block

vf: final velocity

v_o: initial velocity

Ff: friction force

F(x): Force

x: distance

You know the values of vf, m and x.

In order to prove the equation (1) it is necessary that you have C The function F(x) for 0 < x < 5, the block's initial velocity, and the value of F.  Thus you can calculate experimentally both sides of the equation.

8 0
2 years ago
A boy drags a suitcase along the ground with a force of 100 N. If the frictional force opposing the motion of the suitcase is 50
stira [4]
Fortunately, 'force' is a vector.  So if you know the strength and direction
of each force, you can easily addum up and find the 'resultant' (net) force.

When we talk in vectors, one newton forward is the negative of
one newton backward.   Hold that thought, while I slog through
the complete solution of the problem.


            (100 N forward) plus (50 N backward)

        =  (100 N forward) minus (50 N forward)

        =           50 N forward .

That's it.
Is there any part of the solution that's not clear ?

4 0
3 years ago
Help me please. <br> A<br> B<br> C<br> D
Y_Kistochka [10]

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5 0
1 year ago
Read 2 more answers
B. Local action and polarization​
algol [13]

Explanation:

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4 0
3 years ago
Three identical springs, each with stiffness 1200 N/m are attached in series (that is, end to end) to make a longer spring to ho
OLga [1]
<h2>Answer:</h2>

400N/m

<h2>Explanation:</h2>

When n identical springs of stiffness k, are attached in series, the reciprocal of their equivalent stiffness (1 / m) is given by the sum of the reciprocal of their individual stiffnesses. i.e

\frac{1}{m} = ∑ⁿ₁ [\frac{1}{k_{i}}]          -----------------------(i)

That is;

\frac{1}{m} = \frac{1}{k_{1}} + \frac{1}{k_{2}} + \frac{1}{k_{3}} + . . . + \frac{1}{k_{n}}      -------------------(ii)

If they have the same value of stiffness say s, then equation (ii) becomes;

\frac{1}{m} = n x \frac{1}{s}           -----------------(iii)

Where;

n = number of springs

From the question,

There are 3 identical springs, each with stiffness of 1200N/m and they are attached in series. This implies that;

n = 3

s = 1200N/m

Now, to calculate the effective stiffness,m, (i.e the stiffness of a longer spring formed from the series combination of these springs), we substitute these values into equation (iii) above as follows;

\frac{1}{m} = 3 x \frac{1}{1200}

\frac{1}{m} = \frac{3}{1200}

\frac{1}{m} = \frac{1}{400}

Cross multiply;

m = 400N/m  

Therefore, the stiffness of the longer spring is 400N/m

7 0
3 years ago
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