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3 years ago

A race car accelerates from 0 m/s ro 30 m/s with a displacement of 45 what is it acceleration

Physics

1 answer:

Minchanka [31]3 years ago

6 0

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If you wanted to do calculations with speed (distance/time), which base units would you use

kap26 [50]

I would use meter and second.
Hope this helps.

4 0

2 years ago

A. How does increasing the voltage of a power supply in an electromagnet affect the strength of the magnetic field?

seropon [69]

PART A)

If we increase the voltage supply in an electromagnet then it will increase the current that is flowing in it

So here due to increase in current there will be increase in the magnetic field due to that electromagnet

PART B)

Here in electric generator the current is produced by rotating a coil between two strong magnets.

So here mechanical energy of rotation of coil is converted into electromagnetic energy.

PART C)

Step up transformer convert the lower voltage input into higher voltage output

here number of turns of coil in output side or secondary number of coils is more than the number of coils in primary side or input side

PART D)

Force on a moving charge is given by

$F = q(\vec v \times \vec B)$

here we know that

q = 0.000600 C

$v = 2.8 \times 10^5 m/s$

B = 4.21 T

now from above equation we have

$F = 0.0006(2.8\times 10^5)(4.21)$

$F = 707.3 N$

direction of force is given by right hand thumb rule

using that rule we got force downwards

7 0

2 years ago

Read 2 more answers

Can you access an instance variable from a static method? explain why or why not.

marusya05 [52]

<span>The reason a static method can't access instance variable is because static references the class not a specific instance of the class so there is no instance variable to access.</span>

5 0

3 years ago

A 250 N force pulls on a box horizontally to the right. The box is moving at constant speed.

lana66690 [7]

Answer:

its 34

Explanation:

3 0

3 years ago

A 1500 kg car traveling 5.0 m/s collides head on with a 3000 kg truck traveling

Setler [38]

m1=1500kg
m_2=3000kg
v_1=5m/s
v_2=7m/s

Using law of conservation of momentum

$\\ \sf\Rrightarrow m_1v_1-m_2v_2=(m1+m2)v_3$

$\\ \sf\Rrightarrow 1500(5)-3000(7)=(1500+3000)v_3$

$\\ \sf\Rrightarrow 7500-21000=4500v_3$

$\\ \sf\Rrightarrow -13500=4500v_3$

$\\ \sf\Rrightarrow v_3=-3m/s$

6 0

2 years ago