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Degger [83]
4 years ago
8

A race car accelerates from 0 m/s ro 30 m/s with a displacement of 45 what is it acceleration

Physics
1 answer:
Minchanka [31]4 years ago
6 0
Hdghehwhevevwgwhhwvsvsvsiosjwbwbwhshbshs
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Which of the following describes a closed conducting loop through which an electrical current can flow?
Romashka-Z-Leto [24]
I think the correct answer is the second option. A circuit describes a closed conducting loop through which an electrical current can flow. It is a path that an electrical current could flow. A circuit could be a closed one or an open circuit. A closed circuit would be a circuit where the current could flow continuously. An open circuit would be a type of circuit where the flow current would only go once and stopped at a particular point since the current has nowhere to go. For a circuit to work, an electric supply should be available to supply the electric current.
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3 years ago
Which of these scientists had the greatest contribution to early microscopy?
attashe74 [19]

Answer:

b

Explanation:

I think im not really sure tho

7 0
3 years ago
Read 2 more answers
Find the net charge of a system consisting of 206 electrons and 161 protons. Express your answer using two significant figures.
kondaur [170]

Answer:

-72\times 10^{-19}C[/tex]

Explanation:

Both electron and proton have the same amount of charge but signs are opposite , electron contains negative charge and proton contain positive charge

Charge on 1 electron = -1.6\times 10^{-19}C

So charge on 206 electron =-206\times 1.6\times 10^{-19}C

Charge on 1 proton = -1.6\times 10^{-19}C

So charge on 161 electron =-106\times 1.6\times 10^{-19}C

So charge of the system = (-206+161)\times 1.6\times 10^{-19}C

=-72\times 10^{-19}C

5 0
3 years ago
Một bóng đèn có hiệu điện thế định mức là 110V. Đặt vào hai đầu bóng đèn các hiệu điện thế sau đây, hỏi trường hợp nào dây tóc c
Leokris [45]

Answer:

fhaiisjrbekxkrkebxnsiiwj4bnds

8 0
3 years ago
A ladybug sits at the outer edge of a turntable, and a gentleman bug sits halfway between her and the axis of rotation. The turn
inn [45]

Answer:

The answer to the question is

The ladybug begins to slide

Explanation:

To solve the question we assume that the frictional force of the ladybug and the gentleman bug are the same

Where the  frictional force equals F_{Friction} = μ×N = m×g×μ

and the centripetal force is given by m·ω²·r

If we denote the properties of the ladybug as 1 and that of the gentleman bug as 2, we have

m₁×g×μ = m₁·ω²·r₁ ⇒ g×μ = ω²·r₁

and for the gentleman bug we have

m₂×g×μ = m₂·ω²·r₂ ⇒ g×μ = ω²·r₂

But r₁ = 2×r₂

Therefore substituting the values of r₁ =2×r₂ we have

g×μ = ω²·r₁ = g×μ = ω²·2·r₂

Therefore   ω²·r₂ = 0.5×g×μ for the ladybug. That is the ladybug has to overcome half the frictional force experienced by the gentleman bug before it start to slide

The ladybug begins to slide

6 0
3 years ago
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