All categories

2 years ago

An object is held 24.8 cm from a lens of focal length 16.0 cm. What is the magnification of the image?

Physics

1 answer:

Gwar [14]2 years ago

3 0

Answer: 1.8

Explanation:

You are given

the object distance U = 24.8 cm

Focal length F = 16.0 cm

First find the image distance by using the formula:

1/f = 1/u + 1/v

Where V = image distance

Substitute u and f into the formula

1/16 = 1/24.8 + 1/v

1/ v = 1/16 - 1/24.8

1/v = 0.0625 - 0.04032258

1/v = 0.022177

Reciprocate both sides by dividing both sides by one

V = 45.09 cm

Magnification M is the ratio of image distance to the object distance. That is,

M = V/U

Substitute V and U into the formula

M = 45.09/24.8

M = 1.818

Magnification of the image is therefore equal to 1.8 approximately

You might be interested in

Instantaneous angular speed is: Group of answer choices the rate at which the angular acceleration is changing total angular dis

Ludmilka [50]

Answer: magnitude of the instantaneous angular velocity

Explanation:

Instantaneous angular speed is refered to as the magnitude of the instantaneous angular velocity. We should note that the instantaneous angular velocity is the rate that has to do with the rotation of an object in circular path.

5 0

2 years ago

Describe in a couple sentences how the index of refraction is related to the speed of light?

lesantik [10]

Answer: n = c / v" "c" is the speed of light in a vacuum, "v" is the speed of light in that substance and "n" is the index of refraction. According to the formula, the index of refraction is the relation between the speed of light in a vacuum and the speed of light in a substance.

Explanation: the relation is the vacuum and the speed of light in a substance.

3 0

2 years ago

Suppose I have a spherical insulating shell with inner radius r and outer radius R. The shell has a uniformly distributed charge

a_sh-v [17]

Answer:

3Q / 4 pi (R^3 - r^3)

Explanation:

Charge density = charge / volume

volume of a spherical shell = $\frac{4}{3} \pi(R^{3} - r^{3})$

4 0

3 years ago

The current in resistor Y is..?

Aliun [14]

(A)

Explanation:

We can see that the resistors are connected in parallel so all of them have the same voltage of 100 V. We also know that

$P = VI$

Since resistor Y dissipates 100 W of power, we can solve for the current as

$I = \dfrac{P}{V} = \dfrac{100\:\text{W}}{100\:\text{V}} = 1.0\:\text{A}$

4 0

2 years ago

Someone please help? :)

Gnoma [55]

Answer:

(A) $F_N - mg\cos\theta$

Explanation:

The net force perpendicular to the surface of the incline is the sum of the gravity force component, which is mgcos(theta), and the reactionary normal force caused by the surface of the incline. The sum is F_N - mgcos(theta) and is usually 0 which is why the object is not moving perpendicularly to the surface of the incline.

8 0

3 years ago