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Free_Kalibri [48]
3 years ago
10

A beaker has a mass of 125g. What is the mass of this beaker in decigrams

Physics
1 answer:
Anit [1.1K]3 years ago
4 0
1250 decigrams
1 gram = 10 decigrams
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Na+/k+–atpase is considered to be an electrogenic pump because
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3 years ago
Diego is playing basketball. While running at 7 km/h toward Gino, he passes the ball to Gino horizontally. The ball travels at 2
enot [183]

TheThe  relative velocity of Deigo will be 27km/h .

<h3>What is relative Velocity? </h3>

The relative velocity is the velocity of an object with respect to another observer. It is the time rate of relative position of one object with respect to another object .

Vab = Va-Vb

Where a is object and b is observer .

We have given here the velocity of ball 20km/ h

and the another velocity is 7km/ h

Let us assume that Diego is also moving in the direction where ball is moving so the relative velocity  will  be

 V = 20+7=27km/ h

When both observer and object is moving in same direction than there sum of velocity will be relative velocity ,if they are moving opposite than subtraction.

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3 0
1 year ago
While refrigerant 410a is a near azeotropic refrigerant, it is still best when charging to remove the r-410a as a _______ from t
andreev551 [17]
While refrigerant 410a is a near azeotropic refrigerant, it is still best when charging to remove the r-410a as a liquid from the storage cylinder.
Azeotrope means a constant boiling mixture. it is a mixture of two or more liquids,by simple distillation whose proportions cannot be changed. A mixture behaving purely is azeotropic and the mixture which behave differently is called non-azeotropic.
7 0
3 years ago
A 70 kg human sprinter can accelerate from rest to 10 m/s in 3.0 s. During the same time interval, a 30 kg greyhound can go from
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Answer:

P_1 = 1166.7 Watt

P_2 = 2000 Watt

Explanation:

Average power for the human sprinter is given as

Power = \frac{\Delta E}{\Delta t}

so we have

P = \frac{\frac{1}{2}mv^2 - 0}{\Delta t}

P = \frac{\frac{1}{2}(70)(10^2) - 0}{3}

P_1 = 1166.7 Watt

Average power for greyhound is given as

P = \frac{\frac{1}{2}mv^2 - 0}{\Delta t}

P = \frac{\frac{1}{2}(30)(20^2) - 0}{3}

P_2 = 2000 Watt

3 0
3 years ago
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