Answer:
10 and 7x + 1
Step-by-step explanation:
The area of a rectangle is 70x + 10.
Let's factor 70x + 10.
Factor out a common factor of 10.
70x + 10 = 10(7x + 1)
Since the area of a rectangle is length * width, we can let one factor be the length and the other factor be the width.
Possible dimensions are 10 and 7x + 1
The two numbers are the same, which is 202
The line segment HI has length 3<em>x</em> - 5, and IJ has length <em>x</em> - 1.
We're told that HJ has length 7<em>x</em> - 27.
The segment HJ is made up by connecting the segments HI and IJ, so the length of HJ is equal to the sum of the lengths of HI and IJ.
This means we have
7<em>x</em> - 27 = (3<em>x</em> - 5) + (<em>x</em> - 1)
Solve for <em>x</em> :
7<em>x</em> - 27 = (3<em>x</em> + <em>x</em>) + (-5 - 1)
7<em>x</em> - 27 = 4<em>x</em> - 6
7<em>x</em> - 4<em>x</em> = 27 - 6
3<em>x</em> = 21
<em>x</em> = 21/3
<em>x</em> = 7