All categories

6 months ago

Use the graph to answer the question.The graph is a transformation of which of the following functions?

Mathematics

1 answer:

Mars2501 [29]6 months ago

3 0

we have that

the parent function of the given graph

is the function

$f(x)=\sqrt[3]{x}$

therefore

<h2>the answer is option A</h2>

You might be interested in

Sawyer got a gift card for his birthday and

Nady [450]

Answer:

<em>Sawyer has to pay $10 each week to pay his mom back</em>

Step-by-step explanation:

Sawyer got a gift card that he wants to use to purchase a video game that costs $60, but he can only cover 50% of it, that is, $30.

The remaining $30 will be covered by his mom, given he pays the money back in three weeks.

If he pays the same amount each week, then each week he should pay $30 / 3 = $10

Sawyer has to pay $10 each week to pay his mom back

5 0

2 years ago

If a person draws a playing card and checks its suit and then spins a three-space spinner, describe the sample space of possible

3241004551 [841]

Answer:

Step-by-step explanation:

5 0

3 years ago

Robin bought 4 feet of string.She uses 10 inches to make each necklace and 6 inches to make each bracelet. If she makes 4 bracel

Nataly [62]

She can make 2 necklaces with 4 inches remaining of string.

7 0

2 years ago

Read 2 more answers

An article gave the following summary information for fracture strengths (MPa) of n = 196 ceramic bars fired in a particular kil

Oliga [24]

Answer:

54.80 MPa to 55.92 MPa

Step-by-step explanation:

Sample mean fracture strength (x) = 55.36 MPa

Sample standard deviation (s) = 3.99 MPa

Sample size (n) = 196.

The upper and lower bounds for a 95% confidence interval are given by:

$U=x+1.960*\frac{s}{\sqrt{n}} \\L=x-1.960*\frac{s}{\sqrt{n}}$

The upper and lower bounds of the confidence interval are;

$U=55.36+1.960*\frac{3.99}{\sqrt{196}}\\U= 55.92\\L=55.36-1.960*\frac{3.99}{\sqrt{196}}\\L= 54.80\\$

The 95% confidence interval for true average fracture strength is 54.80 MPa to 55.92 MPa

4 0

3 years ago

What is the distance of a car traveling with a velocity of 20 m/s north in 5 seconds

blsea [12.9K]

distance=velocity×

(time)

20(5)

=100m/S

3 0

2 years ago