A 1 L sample of CO initially at STP is heated to 546 K, and its volume is increased to 2 L, the final pressure of CO is 1 atm.
We have,
Initial volume, V₁ = 1 L
Final volume, V₂ = 2 L
Initial temperature, T₁ = 273 K (standard temperature)
Final temperature, T₂ = 546 K
Initial pressure, P₁ = 1 atm
Final pressure, P₂ = ?
To calculate final pressure, we will use combined gas law.
Combined gas law is given as -
<u>P₁V₁</u> = <u>P₂V₂</u>
T₁ T₂
where,
P₁ = initial pressure
P₂ = final pressure
V₁ = initial volume
V₂ = final volume
T₁ = initial temperature
T₂ = final temperature
Substituting values in the gas law equation -
<u> 1 x 1 </u> = <u>P₂ x 2</u>
273 546
P₂ = <u> 546 x 1 x 1</u> atm
273 x 2
P₂ = 1 atm
Therefore, the final pressure of sample of CO at STP is 1 atm.
To learn more about volume at STP,
brainly.com/question/4129937
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