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3 years ago

If a solution is considered basic, then _____________

Chemistry

1 answer:

Mrrafil [7]3 years ago

7 0

Describe the concentration of hydrogen ions in the solution and increase on a negative logarithmic scale

ANSWER
(A)

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Please help me vote you brainiest

xxTIMURxx [149]

Answer: D

Explanation: P = W/t

W = F d

When dividing, if you have a large number over a small, you get a large number. We want a small number, so we want the opposite for our P : W/ t formula. We want a small Work and a large time.

Right off the bat, the two with the least time aren't right then.

From there, we can estimate how much work it would take using the W = F d equation. If there is a small distance, there is less work, which is what we want to achieve a small work over large time.

So, the choice with the most time and the least distance should be correct.

3 0

2 years ago

Be sure to answer all parts. The equilibrium constant (Kp) for the reaction below is 4.40 at 2000. K. H2(g) + CO2(g) ⇌ H2O(g) +

nikklg [1K]

Answer:

For 1: The value of $\Delta G$ for the chemical equation is -24.636 kJ/mol

For 2: The value of $\Delta G$ for the chemical equation is -20.925 kJ/mol

Explanation:

For the given chemical equation:

$H_2(g)+CO_2(g)\rightleftharpoons H_2O(g)+CO(g)$

For 1:

To calculate the $\Delta G$ for given value of equilibrium constant, we use the relation:

$\Delta G=-RT\ln K_p$ .....(1)

where,

$\Delta G$ = ? kJ/mol

R = Gas constant = $8.314J/K mol$

T = temperature = 2000 K

$K_p$ = equilibrium constant in terms of partial pressure = 4.40

Putting values in above equation, we get:

$\Delta G=-(8.314J/Kmol)\times 2000K\times \ln (4.40)\\\\\Delta G=-24636.12J/mol$

Converting this into kilo joules, we use the conversion factor:

1 kJ = 1000 J

So, -24636.12 J/mol = -24.636 kJ/mol

Hence, the value of $\Delta G$ for the chemical equation is -24.636 kJ/mol

For 2:

The expression of $K_p$ for the given chemical equation is:

$K_p=\frac{p_{CO}p_{H_2O}}{p_{H_2}p_{CO_2}}$

We are given:

$p_{CO}=1.18atm\\p_{H_2O}=0.66atm\\p_{CO_2}=0.82atm\\p_{H_2}=0.27atm$

Putting values in above equation, we get:

$K_p=\frac{1.18\times 0.66}{0.27\times 0.82}\\\\K_p=3.52$

Now, calculating the value of $\Delta G$ by using equation 1:

R = Gas constant = $8.314J/K mol$

T = temperature = 2000 K

$K_p$ = equilibrium constant in terms of partial pressure = 3.52

Putting values in equation 1, we get:

$\Delta G=-(8.314J/Kmol)\times 2000K\times \ln (3.52)\\\\\Delta G=-20925.68J/mol$

Converting this into kilo joules, we use the conversion factor:

1 kJ = 1000 J

So, -20925.68 J/mol = -20.925 kJ/mol

Hence, the value of $\Delta G$ for the chemical equation is -20.925 kJ/mol

3 0

3 years ago

Read 2 more answers

This is an impossible formula. Pretend it is real.

guapka [62]

There are eight moles of oxygen atoms in 1 mole of $Mn_{9}(ClO_{4}) _{2}$ .

<h3>What is the number of moles of oxygen atoms?</h3>

We know that a compound is composed of atoms. The atoms that make up the molecule are chemically combined. It is usual that the number of atoms in the compound would correspond with the chemical formula.

Now we have the compound $Mn_{9}(ClO_{4}) _{2}$ . In one mole of the compound we have;

9 Moles of manganese atom
2 moles of chlorine atom
8 moles of oxygen atom

Thus, there are eight moles of oxygen atoms in 1 mole of $Mn_{9}(ClO_{4}) _{2}$ .

Learn more about atoms;brainly.com/question/1566330

#SPJ1

7 0

2 years ago

PLS HELP!!

zimovet [89]

Answer:

if its a multiple question answer its hydroden and carbon

if not its carbon

3 0

3 years ago

Part

r-ruslan [8.4K]

The molar concentration will be greater than 0.01 M $KIO_{3}$ .

Since more of the compound was measured out than what was calculated, you can think of the solution as being 'stronger' than what it was calculated to be. Since a 'stronger' concentration results in a number that is higher, the molarity of this solution is going to be greater than 0.01 M.

7 0

3 years ago