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jeyben [28]
3 years ago
10

1. For dry air at 1.0000 atm pressure, the densities at –50°C, 0°C, and 69°C are 1.5826 g dm–3 , 1.2929 g dm–3, and 1.0322 g dm–

3, respectively. a) Assume a sample of mass 1000 g, and calculate the volume at each temperature. b) From these data, and assuming that air obeys Charles’s law, determine a value for th
Chemistry
1 answer:
pshichka [43]3 years ago
8 0

Answer :

(a) The value of volume of air at temperature -50^oC,0^oC\text{ and }69^oC are 631.87dm^3,773.46dm^3\text{ and }968.80dm^3 respectively.

Explanation :

(a) The formula used for density is:

Density=\frac{Mass}{Volume}

or,

Volume=\frac{Mass}{Density}

Now we have to calculate the volume at each temperature.

The mass of sample = 1000 g

<u>At temperature -50^oC :</u>

Density = 1.5826g/dm^3

Volume=\frac{1000g}{1.5826g/dm^3}=631.87dm^3

<u>At temperature 0^oC :</u>

Density = 1.2929g/dm^3

Volume=\frac{1000g}{1.2929g/dm^3}=773.46dm^3

<u>At temperature 69^oC :</u>

Density = 1.0322g/dm^3

Volume=\frac{1000g}{1.0322g/dm^3}=968.80dm^3

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Explanation:

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