Question

1. For dry air at 1.0000 atm pressure, the densities at –50°C, 0°C, and 69°C are 1.5826 g dm–3 , 1.2929 g dm–3, and 1.0322 g dm–3, respectively. a) Assume a sample of mass 1000 g, and calculate the volume at each temperature. b) From these data, and assuming that air obeys Charles’s law, determine a value for th

Answer 1

Answer :

(a) The value of volume of air at temperature $-50^oC,0^oC\text{ and }69^oC$ are $631.87dm^3,773.46dm^3\text{ and }968.80dm^3$ respectively.

Explanation :

(a) The formula used for density is:

$Density=\frac{Mass}{Volume}$

or,

$Volume=\frac{Mass}{Density}$

Now we have to calculate the volume at each temperature.

The mass of sample = 1000 g

At temperature $-50^oC$ :

Density = $1.5826g/dm^3$

$Volume=\frac{1000g}{1.5826g/dm^3}=631.87dm^3$

At temperature $0^oC$ :

Density = $1.2929g/dm^3$

$Volume=\frac{1000g}{1.2929g/dm^3}=773.46dm^3$

At temperature $69^oC$ :

Density = $1.0322g/dm^3$

$Volume=\frac{1000g}{1.0322g/dm^3}=968.80dm^3$