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Nata [24]
3 years ago
14

A student has a flask containing two immiscible liquids. One of the liquids is a solution of a solid in water. Describe how you

would separate the mixture into three separate components.
Chemistry
2 answers:
Oksanka [162]3 years ago
6 0

The mixture can be separated into three separate components by using a centrifuge and a separating funnel.

A centrifuge is used to separate a solid that is held in suspension by a liquid. In this case a solid dissolved in water. In contrast, a separating funnel is used to separate two immiscible liquids.

-First take the flask containing the two immiscible liquids and pour contents in to a closed separating funnel.

- The most dense liquid will settle at the bottom, then open the separating funnel valve to collect contents of dense liquid into a flask.

- The remaining liquid on the separating funnel can be collected in a different flask.

-Now take the liquid that is a solution of a solid in water and pour in a test tube. Place the contents in a centrifuge.

- Centrifuge at high speed until the solid sinks to the bottom of the test tube, then decant the liquid into a flask and the solid remains in the test tube

I am Lyosha [343]3 years ago
3 0

Answer:

It can be separated using a separating funnel followed by crystallization.

Explanation:

First the mixture is put into a separating funnel. This will separate the two immiscible liquids. When the two immiscible liquids are separated, we recall that one is a solution of a solid solute and we wish to recover the solid from the solution whilst recovering the solvent also.

The solid can only be recovered by crystalization if we do not want to loose the solvent. Seeds of already crystalized solute may be added to system to induce crystalization.

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Which of the following equations of CH4 + Cl2
mylen [45]

Balanced equation : C. CH₄ + 4Cl₂⇒  CCl₄+ 4HCl

<h3>Further explanation  </h3>

Equalization of chemical reactions can be done using variables. Steps in equalizing the reaction equation:  

1. gives a coefficient on substances involved in the equation of reaction such as a, b, or c, etc.  

2. make an equation based on the similarity of the number of atoms where the number of atoms = coefficient × index (subscript) between reactant and product  

3. Select the coefficient of the substance with the most complex chemical formula equal to 1  

Reaction

CH₄ + Cl₂⇒  CCl₄+ HCl

  • Give coefficient :

aCH₄ + bCl₂⇒  CCl₄+ cHCl

  • Make equation :

C, left=a, right=1⇒a=1

H, left=4a, right=c⇒4a=c⇒4.1=c⇒c=4

Cl, left=2b, right=4+c⇒2b=4+c⇒2b=4+4⇒2b=8⇒b=4

The equation becomes :

CH₄ + 4Cl₂⇒  CCl₄+ 4HCl

3 0
3 years ago
Problem Page Question It takes to break a carbon-carbon single bond. Calculate the maximum wavelength of light for which a carbo
Marizza181 [45]

This is a incomplete question. The complete question is:

It takes 348 kJ/mol to break a carbon-carbon single bond. Calculate the maximum wavelength of light for which a carbon-carbon single bond could be broken by absorbing a single photon. Round your answer to correct number of significant digits

Answer: 344 nm

Explanation:

E=\frac{Nhc}{\lambda}

E= energy  = 348kJ= 348000 J  (1kJ=1000J)

N = avogadro's number = 6.023\times 10^{23}

h = Planck's constant = 6.626\times 10^{-34}Js&#10;

c = speed of light = 3\times 10^8ms^{-1}

348000=\frac{6.023\times 10^{23}\times 6.626\times 10^{-34}\times 3\times 10^8}{\lambda}

\lambda=\frac{6.023\times 10^{23}\times 6.626\times 10^{-34}\times 3\times 10^8}{348000}

\lambda=3.44\times 10^{-7}m=344nm    1nm=10^{-9}m

Thus the maximum wavelength of light for which a carbon-carbon single bond could be broken by absorbing a single photon is 344 nm

5 0
3 years ago
A red car and a blue car collide. What would be an example of Locard's exchange principle in this situation?
Lelu [443]

Answer:

The blue car left paint on the red car

Explanation:

8 0
3 years ago
I'm stuck on this assignment, +20 PTS and BRAINLIEST for step by step:
dolphi86 [110]

Answer:

2. 2.74 L

3. 488 K

4. 7.47 L

5. 38.6 L

6. 2.85 mol

7. 319 K

8. 3.43 kPa

Explanation:

Generally speaking, you want to convert units to SI units, but in this case, we are working with ratios.  This makes up for using the units that wouldn't appropriate elsewhere.

2.  Use the equation P₁V₁ = P₂V₂.  Solve for V₂.  

(3.05 L)(870 kPa) = (969 kPa)(V₂)  

V₂ = 2.74 L.  

3.  Use the equation V₁/T₁ = V₂/T₂. Solve for T₂.  

(3.32 L)/(360 K) = (4.50 L)/(T₂)  

T₂ = 488 K.

4.  Do the same as above, but for V₂.  

(5.10 L)/(-56°C) = V₂/(-82°C)  

V₂ = 7.47 L

5.  Use the equation V₁/n₁ = V₂/n₂.  Solve for V₂.  

(37.2 L)/(0.750 mol) = (V₂)/(0.778 mol)  

V₂ = 38.6 L

6.  Do the same as above, but for n₂.

(86.0 L)/(2.65 mol) = (92.5 L)(n₂)  

n₂ = 2.85 mol

7.  Use the equation P₁/T₁ = P₂/T₂.  Solve for T₂.  

(3.00 atm)/(390 K) = (2.45 atm)/(T₂)  

T₂ = 319 K

8.  Do the same as above, but for P₂.  

In this specific case, however you will need to convert units.  Since both temperatures don't have the same sign, the ratio won't come out right.  Convert to Kelvin.  Add 273.15 to the temperature in Celsius to convert to Kelvin -12.3°C = 260.85 K  25°C = 298.15 K.

(3.00 kPa)/(260.85 K) = P₂/(298.15 K)

P₂ = 3.43 kPa

There is a lot in here... If you are confused about something, let me know!

6 0
3 years ago
What parts of a wave are used to determine the wavelength of that wave
Ann [662]
The trough and the hill part
7 0
3 years ago
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