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Nata [24]
3 years ago
14

A student has a flask containing two immiscible liquids. One of the liquids is a solution of a solid in water. Describe how you

would separate the mixture into three separate components.
Chemistry
2 answers:
Oksanka [162]3 years ago
6 0

The mixture can be separated into three separate components by using a centrifuge and a separating funnel.

A centrifuge is used to separate a solid that is held in suspension by a liquid. In this case a solid dissolved in water. In contrast, a separating funnel is used to separate two immiscible liquids.

-First take the flask containing the two immiscible liquids and pour contents in to a closed separating funnel.

- The most dense liquid will settle at the bottom, then open the separating funnel valve to collect contents of dense liquid into a flask.

- The remaining liquid on the separating funnel can be collected in a different flask.

-Now take the liquid that is a solution of a solid in water and pour in a test tube. Place the contents in a centrifuge.

- Centrifuge at high speed until the solid sinks to the bottom of the test tube, then decant the liquid into a flask and the solid remains in the test tube

I am Lyosha [343]3 years ago
3 0

Answer:

It can be separated using a separating funnel followed by crystallization.

Explanation:

First the mixture is put into a separating funnel. This will separate the two immiscible liquids. When the two immiscible liquids are separated, we recall that one is a solution of a solid solute and we wish to recover the solid from the solution whilst recovering the solvent also.

The solid can only be recovered by crystalization if we do not want to loose the solvent. Seeds of already crystalized solute may be added to system to induce crystalization.

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Consider the equilibrium reaction and its equilibrium constant expression. Br 2 ( g ) + 2 NO ( g ) − ⇀ ↽ − 2 NOBr ( g ) K = [ NO
zavuch27 [327]

Answer:

K_2=\frac{[NOBr]^4_{eq}}{[NO]^4_{eq}[Br]^2_{eq}}

Explanation:

Hello,

In this case, for the equilibrium condition, the equilibrium constant is defined via the law of mass action, which states that the division between the concentrations of the products over the concentration of the reactants at equilibrium equals the equilibrium constant, for the given reaction:

2 Br_2 ( g ) + 4 NO ( g ) \rightleftharpoons  4NOBr ( g )

The suitable equilibrium constant turns out:

K_2=\frac{[NOBr]^4_{eq}}{[NO]^4_{eq}[Br]^2_{eq}}

Or in terms of the initial equilibrium constant:

K_2=K_1^2

Since the second reaction is a doubled version of the first one.

Best regards.

5 0
3 years ago
Compound X has a molar mass of 316.25 g*mol^-1 and the following composition:
Leokris [45]

Answer:

Compound X has a molar mass of 316.25 g*mol^-1 and the following composition:

element & mass %

phosphorus & 39.18%

sulfur & 60.82%

Write the molecular formula of X.

Explanation:

The given molecule of phosphorus and sulfur has molar mass --- 316.25 g.

Empirical formula calculation:                      

element:              phosphorus                       sulfur

co9mposition:      39.185%                            60.82%

divide with

atomic mass:          39.185/31.0 g/mol           60.82/32.0g/mol

                              =1.26mol                           1.90mol

smallest mole ratio:   1.26mol/1.26mol =1      1.90mol/1.26 mol =1.50

multiply with 2:          2                                         3

Hence, the empirical formula is:

P2S3.

Mass of empirical formula is:

158.0g/mol

Given, molecule has molar mass --- 316.25 g/mol

Hence, the ratio is:

316.25g/mol/158.0 =2

Hence, the molecular formula of the compound is :

2 x (P2S3)

=P_4S_6

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