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Nata [24]
3 years ago
14

A student has a flask containing two immiscible liquids. One of the liquids is a solution of a solid in water. Describe how you

would separate the mixture into three separate components.
Chemistry
2 answers:
Oksanka [162]3 years ago
6 0

The mixture can be separated into three separate components by using a centrifuge and a separating funnel.

A centrifuge is used to separate a solid that is held in suspension by a liquid. In this case a solid dissolved in water. In contrast, a separating funnel is used to separate two immiscible liquids.

-First take the flask containing the two immiscible liquids and pour contents in to a closed separating funnel.

- The most dense liquid will settle at the bottom, then open the separating funnel valve to collect contents of dense liquid into a flask.

- The remaining liquid on the separating funnel can be collected in a different flask.

-Now take the liquid that is a solution of a solid in water and pour in a test tube. Place the contents in a centrifuge.

- Centrifuge at high speed until the solid sinks to the bottom of the test tube, then decant the liquid into a flask and the solid remains in the test tube

I am Lyosha [343]3 years ago
3 0

Answer:

It can be separated using a separating funnel followed by crystallization.

Explanation:

First the mixture is put into a separating funnel. This will separate the two immiscible liquids. When the two immiscible liquids are separated, we recall that one is a solution of a solid solute and we wish to recover the solid from the solution whilst recovering the solvent also.

The solid can only be recovered by crystalization if we do not want to loose the solvent. Seeds of already crystalized solute may be added to system to induce crystalization.

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A student is trying to calculate the density of a ball. She already knows the mass, but she needs to determine the volume as wel
murzikaleks [220]

Answer:

V equals four-thirds times pi times r cubed

Explanation:

Volume = a³ , where a is length of each side. Volume = l × w × h , where l is length, w is width and h is height. Volume = 4/3 πr³ , where r is the radius. Volume = πr²h , where r is the radius and h is the height.

7 0
3 years ago
The partial pressure of hellium gas in a gaseous mixture of hellium and hydrogen is<br>​
RUDIKE [14]

Answer:

The partial pressure of helium gas in a gaseous mixture of helium and hydrogen is the pressure that the helium would exert in the absence of the hydrogen. equal to the total pressure divided by helium's molar mass. O equal to the total pressure divided by the number of helium atoms present.

Hope this Helps (✿◡‿◡)

8 0
3 years ago
A gas mixture contains helium (He ), argon (Ar) , neon (Ne ), Xenon ( Xe), and krypton (Kr) gases. The total pressure of the gas
MA_775_DIABLO [31]

Answer:

0.488atm = Pressure Kr

Explanation:

The total pressure in a mixture of gases could be defined as the sum of the partial pressures of a mixture. For the mixture of gases in the problem:

Total pressure = Pressure He + Pressure Ar + Pressure Ne + Pressure Xe + Pressure Kr

Converting the total pressure to atm:

1252.5mm Hg * (1atm / 760 mmHg) = 1.648 atm

Replacing:

1.648atm = 0.32atm + 0.21atm + 0.44atm + 0.19atm + Pressure Kr

<h3>0.488atm = Pressure Kr</h3>
5 0
3 years ago
What is the number of valence electrons in a nitrogen atom in the ground state
ddd [48]

Answer: 5

Explanation:

It just is

6 0
3 years ago
How many grams of sodium chloride decompose to yield 15 grams of chlorine gas?
defon

Answer:

24.6g of NaCl

Explanation:

Expression of the reaction:

            2NaCl →  2Na  +  Cl₂

Given parameters:

Mass of Cl₂  = 15g

Unknown:

Mass of NaCl  = ?

Solution:

To solve this problem, we have to use mole relationships.

 Find the number of moles of the mass of the given specie;

    Number of moles  = \frac{mass}{molar mass}  

     Molar mass of Cl₂  = 2(35.5) = 71g/mol

   Number of moles  = \frac{15}{71}   = 0.21mole

Now;

 From the balanced reaction equation;

        1 mole of Cl₂ is produced from 2 moles of NaCl;

      0.21 mole of Cl₂ will be produced from 0.21 x 2 = 0.42mole of NaCl

So,

  Mass of NaCl = number of moles x molar mass

    Molar mass of NaCl  = 23 + 35.5 = 58.5g/mol

 Mass of NaCl  = 0.42 x 58.5 = 24.6g of NaCl

8 0
3 years ago
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