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Tomtit [17]
11 months ago
10

Alice evaluated the expression below but got an incorrect answer. 12• (0.25) • (-8) ÷ 1/3 • 53• (8) ÷ 1/3 • 524 • 1/3 • 58 • 540

Find and describe Alice's error(s)Find the correct value of the expression.
Mathematics
1 answer:
MrMuchimi11 months ago
5 0

12• (0.25) • (-8) ÷ 1/3 • 5

3• (8) ÷ 1/3 • 5

24 • 1/3 • 5

8 • 5

40

Until the second step is ok.

in the third step, she multiplied the 1/3 term instead if dividing it

24 ÷ 1/3 . 5

24 ÷ 5/3

72/5

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What is the slope of a line that passes through the origin and the point (-2,1)?
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How do you simplify this?<br>x²y+xy² / y²+2/5 × xy​​​
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\huge \boxed{\mathbb{QUESTION} \downarrow}

  • How do you simplify this?
  • x²y+xy² / y²+2/5 × xy

\large \boxed{\mathbb{ANSWER\: WITH\: EXPLANATION} \downarrow}

\sf\frac{  { x  }^{ 2  }  y+x { y  }^{ 2  }    }{  { y  }^{ 2  }  + \frac{ 2  }{ 5  }   \times  xy  } \\

Factor the expressions that are not already factored.

_____

<u>How </u><u>to</u><u> factorise</u><u> </u><u>:</u><u>-</u>

<u>NUMERATOR</u> \downarrow

\sf \: x ^ { 2 } y + x y ^ { 2 }

Factor out xy.

\sf \: xy\left(x+y\right)

<u>DENOMINATOR</u> \downarrow

\sf{ y  }^{ 2  }  + \frac{ 2  }{ 5  }   \times  xy \\

Factor out 1/5.

\sf \: {\frac{1}{5}y\left(2x+5y\right)}  \\

_____

Continuing...

\sf\frac{xy\left(x+y\right)}{\frac{1}{5}y\left(2x+5y\right)}  \\

Cancel out y in both the numerator and denominator.

\sf\frac{x\left(x+y\right)}{\frac{1}{5}\left(2x+5y\right)}  \\

Expand the expression.

\sf\frac{x^{2}+xy}{\frac{2}{5}x+y}  \\

This can further simplified to as \downarrow

=    \boxed{\boxed{\bf\frac{5x\left(x  +y\right)}{2x+5y}}}

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