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zimovet [89]
1 year ago
8

A home improvement store is giving away 10% off coupons to every 10th customer, 20% off coupons to every 25th customer, and a fr

ee workshop lesson to every 100th customer. What customer will be the first to receive all three prizes?
Mathematics
1 answer:
ololo11 [35]1 year ago
8 0

The first common multiple between 100, 25, and 10, is 100.

This means that the first customer that receives the 3 prizes is the 100th customer.

<h3>What customer will be the first to receive all 3 prizes?</h3>

Here we know that:

  • Every 10th customer gets the 10% coupon.
  • Every 25th customer gets the 20% coupon.
  • Every 100th customer gets the free workshop.

The first customer that gets the 3 prizes is a customer that is a 10th customer, a 25th customer, and a 100th customer at the same time.

Then we need to find the first common multiple between 10, 25, and 100.

This is really trivial, as we know that:

10*10 = 100

So 100 is a multiple of 10.

25*4 = 100

So 100 is a multiple of 25.

Then the first common multiple between 100, 25, and 10, is 100.

This means that the first customer that receives the 3 prizes is the 100th customer.

If you want to learn more about common multiples:

brainly.com/question/10749076

#SPJ1

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The probability distribution for the rate of return on an investment is
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Answer:

a)0.7

b) 10.03

c)  0.0801

Step-by-step explanation:

Rate of return   Probability

9.5                           0.1

9.8                           0.2

10                             0.3

10.2                          0.3

10.6                          0.1

a.

P(Rate of return is at least 10%)=P(R=10)+P(R=10.2)+P(R=10.6)

P(Rate of return is at least 10%)=0.3+0.3+0.1

P(Rate of return is at least 10%)=0.7

b)

Expected rate of return=E(x)=sum(x*p(x))

Rate of return(x)   Probability(p(x))    x*p(x)

9.5                           0.1                       0.95

9.8                           0.2                      1.96

10                             0.3                        3

10.2                          0.3                        3.06

10.6                          0.1                       1.06

Expected rate of return=E(x)=sum(x*p(x))

Expected rate of return=0.95+1.96+3+3.06+1.06=10.03

c)

variance of the rate of return=V(x)=sum(x^2p(x))-[sum(x*p(x))]^2

Rate of return(x)   Probability(p(x))    x*p(x)    x²*p(x)

9.5                           0.1                       0.95       9.025

9.8                           0.2                      1.96         19.208

10                             0.3                       3             30

10.2                          0.3                       3.06        31.212

10.6                          0.1                       1.06         11.236

sum[x²*p(x)]=9.025+19.208+30+31.212+11.236=100.681

variance of the rate of return=V(x)=sum(x²*p(x))-[sum(x*p(x))]²

variance of the rate of return=V(x)=100.681-(10.03)²

variance of the rate of return=V(x)=100.681-100.6009

variance of the rate of return=V(x)=0.0801

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