A rectangle's length, x, is 2 meters greater than its width. If the perimeter of the rectangle is greater than 112 meters, what
is the rectangle's possible length, x, in meters ?
-(can someone please explain how you find the answer to the problem?)
1 answer:
Assume widthis x-2
perimeter is 2*(width+length)
so 2*(x+x-1)>112
2*(2x-1)>112
4x-2>112
x>28.5
so any length greater than 28.5 will work
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