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1 year ago

What is Racemic mixture?

Chemistry

1 answer:

weqwewe [10]1 year ago

3 0

Racemic mixture

An equimolar mixture of the enantiomers is called Racemic mixture. It may be represented as dl or (±)

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Find the atomicity of water.

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One molecule of water contains two atoms of hydrogen and one atom of oxygen, the atomicity of water is three.

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3 years ago

True or False: If you have a covalent compound, the first element written in the formula will always be a nonmetal

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3 years ago

Phosgene, COCl2, gained notoriety as a chemical weapon in World War I. Phosgene is produced by the reaction of carbon monoxide w

jek_recluse [69]

The question is incomplete, here is the complete question:

Phosgene, $COCl_2$ , gained notoriety as a chemical weapon in World War I. Phosgene is produced by the reaction of carbon monoxide with chlorine:

$CO(g)+Cl_2(g)\rightleftharpoons COCl_2(g)$

The value of $K_c$ for this reaction is 5.79 at 570 K. What are the equilibrium partial pressures of the three gases if a reaction vessel initially contains a mixture of the reactants in which $p_{CO}=p_{Cl_2}=0.265atm$ and $p_{COCl_2}=0.000atm$ ?

Answer: The equilibrium partial pressure of CO, $Cl_2\text{ and }COCl_2$ is 0.257 atm, 0.257 atm and 0.008 atm respectively.

Explanation:

The relation of $K_c\text{ and }K_p$ is given by:

$K_p=K_c(RT)^{\Delta n_g}$

$K_p$ = Equilibrium constant in terms of partial pressure

$K_c$ = Equilibrium constant in terms of concentration = 5.79

$\Delta n_g$ = Difference between gaseous moles on product side and reactant side = $n_{g,p}-n_{g,r}=1-2=-1$

R = Gas constant = $0.0821\text{ L. atm }mol^{-1}K^{-1}$

T = Temperature = 570 K

Putting values in above equation, we get:

$K_p=5.79\times (0.0821\times 570)^{-1}\\\\K_p=0.124$

We are given:

Initial partial pressure of CO = 0.265 atm

Initial partial pressure of chlorine gas = 0.265 atm

Initial partial pressure of phosgene = 0.00 atm

The given chemical equation follows:

$CO(g)+Cl_2(g)\rightleftharpoons COCl_2(g)$

Initial: 0.265 0.265

At eqllm: 0.265-x 0.265-x x

The expression of $K_p$ for above equation follows:

$K_p=\frac{p_{COCl_2}}{p_{CO}\times p_{Cl_2}}$

Putting values in above equation, we get:

$0.124=\frac{x}{(0.265-x)\times (0.265-x)}\\\\x=0.0082,8.59$

Neglecting the value of x = 8.59 because equilibrium partial pressure cannot be greater than initial pressure

So, the equilibrium partial pressure of CO = $(0.265-x)=(0.265-0.008)=0.257atm$

The equilibrium partial pressure of $Cl_2=(0.265-x)=(0.265-0.008)=0.257atm$

The equilibrium partial pressure of $COCl_2=x=0.008atm$

Hence, the equilibrium partial pressure of CO, $Cl_2\text{ and }COCl_2$ is 0.257 atm, 0.257 atm and 0.008 atm respectively.

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3 years ago

Why does sugar taste sweet PLEASE EXPLAIN

pshichka [43]

Answer:

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3 years ago

4. Arrange the following substances in order of increasing boiling point: CH3CH2OH, HOCH2CH2OH, CH3CH2Cl , and ClCH2CH2OH A. CH3

Studentka2010 [4]

Answer: Option (B) is the correct answer.

Explanation:

A molecules that will have more number of hydrogen bonding will has highest boiling point because to break the hydrogen bonds high heat needs to be provided.

So, in the molecule $HOCH_{2}CH_{2}OH$ there is presence of two alcoholic groups. Hence, it will have strongest hydrogen bonding as compared to the rest of molecules.

In the molecule $ClCH_{2}CH_{2}OH$ there will be hydrogen bonding and dipole-dipole interactions. Hence, it boiling point will be slightly less than $HOCH_{2}CH_{2}OH$ .

In the molecule $CH_{3}CH_{2}OH$ , there will be only hydrogen bonding. Hence, its boiling point is less than $ClCH_{2}CH_{2}OH$ .

In the molecule $CH_{3}CH_{2}Cl$ , there is no hydrogen bonding but there will be only dipole-dipole interactions. Hence, its boiling point will be the least.

Therefore, we can conclude that increasing order of boiling point will be as follows.

$CH_{3}CH_{2}Cl$ < $CH_{3}CH_{2}OH$ < $ClCH_{2}CH_{2}OH$ < $HOCH_{2}CH_{2}OH$

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3 years ago

What is Racemic mixture?​

What is Racemic mixture?