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pickupchik [31]
3 years ago
12

Standard temperature and pressure (STP), in the context of gases, refers to a) 298.15 K and 1 atm b) 273.15 K and 1 atm c) 298.1

5 K and 1 torr d) 273.15 K and 1 pascal e) 273.15 K and 1 torr is a valid statement of Charles' law.
Chemistry
1 answer:
lina2011 [118]3 years ago
7 0

Answer : The correct option is, (B) 273.15 K and 1 atm

Explanation :

STP : STP stands for standard temperature and pressure.

STP conditions :

The temperature is, 0^oC or 273.15K or 32^oF

The pressure is, 1atm or 101.325kPa

The volume is 22.4 L for 1 mole of a substance.

Hence, the correct option is, (B) 273.15 K and 1 atm

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Suppose a 250. mL flask is filled with 0.30 mol of N_2 and 0.70 mol of NO. The following reaction becomes possible:N_2(g) +O2 →
Inessa [10]

Answer:

0.4 M

Explanation:

Equilibrium occurs when the velocity of the formation of the products is equal to the velocity of the formation of the reactants. It can be described by the equilibrium constant, which is the multiplication of the concentration of the products elevated by their coefficients divided by the multiplication of the concentration of the reactants elevated by their coefficients. So, let's do an equilibrium chart for the reaction.

Because there's no O₂ in the beginning, the NO will decompose:

N₂(g) + O₂(g) ⇄ 2NO(g)

0.30 0 0.70 Initial

+x +x -2x Reacts (the stoichiometry is 1:1:2)

0.30+x x 0.70-2x Equilibrium

The equilibrium concentrations are the number of moles divided by the volume (0.250 L):

[N₂] = (0.30 + x)/0.250

[O₂] = x/0.25

[NO] = (0.70 - 2x)/0.250

K = [NO]²/([N₂]*[O₂])

K = \frac{(\frac{0.70 -2x}{0.250})^2 }{\frac{0.30+x}{0.250}*\frac{x}{0.250} }

7.70 = (0.70-2x)²/[(0.30+x)*x]

7.70 = (0.49 - 2.80x + 4x²)/(0.30x + x²)

4x² - 2.80x + 0.49 = 2.31x + 7.70x²

3.7x² + 5.11x - 0.49 = 0

Solving in a graphical calculator (or by Bhaskara's equation), x>0 and x<0.70

x = 0.09 mol

Thus,

[O₂] = 0.09/0.250 = 0.36 M ≅ 0.4 M

3 0
3 years ago
5. Write the names of the following ions.
Talja [164]
A.) Phosphate ion or Orthophosphate
d.) Hydroxide
D.) Ammonium
e.) Iron
C.) Nitrate
f.) Sulfur dioxide
5 0
2 years ago
How many grams of Mg(NO3)2 would be produced? please show how you got the answer​
Len [333]

Answer:

148 grams of relative atomic mass

Explanation:

magnesium atomic mass : 24

nitrogen : 14

oxygen : 16

24 × 1

14 × 1 × 2

16 × 3 × 2

24 + 28 + 80 = 148 grams

7 0
3 years ago
g Calculate the pOH of a solution that results from mixing 23.3 mL of 0.16 M trimethylamine ((CH3)3N) with 44.1 mL of 0.15 M (CH
hichkok12 [17]

Answer:

pOH = 5.961

Explanation:

To find the pH of a weak base we can use Henderson-Hasselbalch equation for weak bases:

pOH = pKb + log [(CH₃)₃NHCl] / [(CH₃)₃N]

<em>Where pKb is -log Kb = 4.187 and [] could be taken as moles of each specie.</em>

<em />

<em>Moles (CH₃)₃NHCl:</em>

0.0441L * (0.15mol/L) = 6.615x10⁻³moles

<em>Moles (CH₃)₃N:</em>

0.0233L * (0.16mol/L) = 3.728x10⁻³moles

And pOH is:

pOH = pKb + log [(CH₃)₃NHCl] / [(CH₃)₃N]

pOH = 4.187 + log [6.615x10⁻³moles] / [3.728x10⁻³moles]

<h3>pOH = 5.961</h3>

<em />

6 0
2 years ago
How many moles of Na3PO4 are in 820. grams of it?
kotegsom [21]

Answer:Hello

D is correct

Explanation:

4 0
2 years ago
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