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3 years ago

Write the empirical formulas of the following compounds: (a) Al2Br6, (b) Na2S2O4, (c) N2O5, (d) K2Cr2O7, (e)H2C2O4.

Chemistry

1 answer:

babunello [35]3 years ago

4 0

Answer:1. $AlBr_3$

2. $NaSO_2$

3. $N_2O_5$

4. $K_2Cr_2O_7$

5. $HCO_2$

Explanation:

Molecular formula is the chemical formula which depicts the actual number of atoms of each element present in the compound.

Empirical formula is the simplest chemical formula which depicts the whole number of atoms of each element present in the compound.

1. $Al_2Br_6$ has empirical formula of $AlBr_3$

2. $Na_2S_2O_4$ has empirical formula of $NaSO_2$

3. $N_2O_5$ has empirical formula of $N_2O_5$

4. $K_2Cr_2O_7$ has empirical formula of $K_2Cr_2O_7$

5. $H_2C_2O_4$ has empirical formula of $HCO_2$

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empirical formula is the simplest ratio of whole numbers of components making up a compound

for 100 g of the compound

N O

mass 46.7 g 53.3 g

number of 46.7 g/ 14 g/mol 53.3 g/ 16 g/mol

moles = 3.34 mol = 3.33 mol

divide by the least number of moles

3.34/3.33 = 1.00 3.33/ 3,33 = 1.00

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N - 1

O - 1

empirical formula is - NO

mass of empirical unit - 14 g/mol + 16 g/mol = 30 g

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number of empirical units = molecular mass / empirical unit mass

= 60.01 g/mol / 30 g = 2

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