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Talja [164]
3 years ago
15

Write the empirical formulas of the following compounds: (a) Al2Br6, (b) Na2S2O4, (c) N2O5, (d) K2Cr2O7, (e)H2C2O4.

Chemistry
1 answer:
babunello [35]3 years ago
4 0

Answer:1. AlBr_3

2. NaSO_2

3.N_2O_5

4. K_2Cr_2O_7

5. HCO_2

Explanation:

Molecular formula is the chemical formula which depicts the actual number of atoms of each element present in the compound.  

Empirical formula is the simplest chemical formula which depicts the whole number of atoms of each element present in the compound.

1. Al_2Br_6 has empirical formula of AlBr_3

2. Na_2S_2O_4 has empirical formula of NaSO_2

3.N_2O_5 has empirical formula of N_2O_5  

4. K_2Cr_2O_7 has empirical formula of K_2Cr_2O_7

5. H_2C_2O_4 has empirical formula of HCO_2  

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Wave speed = frequency x wavelength
                     =       50 x 0.1
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Hope this helps!
7 0
3 years ago
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solution of a weak acid HA has initial concentration c and acid ionization constant Ka. To what concentration should the acid be
soldier1979 [14.2K]

Answer:

The concentration c is equal to Ka

Explanation:

The acid will ionize as observed in the following reaction:

HA = H+ + A-

H+ is the proton of the acid and A- is the conjugate base . The equation to calculate the Ka is as follows:

Ka = ([H+]*[A -])/[HA]

Initially we have to:

[H+] = 0

[A-] = 0

[HA] = c

During the change we have:

[H+] = +x

[A-] = +x

[HA] = -x

During balance we have:

[H+] = 0 + x

[A-] = 0 + x

[HA] = c - x

Substituting the Ka equation we have:

Ka = ([H+]*[A-])/[HA]

Ka = (x * x)/(c-x)

x^2 + Kax - (c * Ka) = 0

We must find c, having as [H+] = 1/2c. Replacing we have:

(1/2c)^2 + (Ka * 1/2 * c) - (c * Ka) = 0

(c^2)/2 + Ka(c / 2 - c) = 0

(c^2)/2 + (-Ka * c/2) = 0

c^2 -(c*Ka) = 0

c-Ka = 0

Ka = c

8 0
3 years ago
Identify the following salts as neutral, acidic, or basic.
allochka39001 [22]

Answer:

1)NH4ClO4: acidic

2)NH4CN: basic

3)LiF: basic

4)KCN: basic

5)LiNO3: neutral

6)NH4Br: acidic

7)SrBr2: neutral

Explanation:

Salt is an ionic compound formed by the neutralization reaction between an acid and a base.The cation of base and anion from an acid combines to form a salt while H+ from acid and OH- from base forms water.

1)NH4Cl4: is an acidic salt formed from neutralization reaction between strong acid and a weak base.

2)NH4CN: is a basic salt formed from neutralization reaction between weak acid and weak base.

3)LiF: basic salt formed from neutralization reaction between strong acid and strong base.

4)KCN: basic salt formed from neutralization reaction between weak acid and strong base.

5)LiNO3: neutral salt formed from neutralization reaction between strong acid and strong base.

6)NH4Br: acidic salt formed from neutralization reaction between strong acid and weak base.

7)SrBr2: neutral acid formed from neutralization reaction between

strong acid and strong base.

4 0
4 years ago
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zhenek [66]

Answer:

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7 0
3 years ago
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SpyIntel [72]

Explanation:

It should be decreasing, and the potential energy increasing, since Law of Conversation of Energy, right?

Also, if you think about what happens when it goes down, it loses potential and gains kinetic, so maybe the opposite should happen when it goes up.

7 0
3 years ago
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