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Alina [70]
3 years ago
13

Classify these molecules as polar or nonpolar. Drag each item to the appropriate bin.

Chemistry
1 answer:
mylen [45]3 years ago
8 0

Answer:

This queston does not provides the molecules that are needed to be checked in order to classify them as polar or non-polar.

Explanation:

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<u>Answer:</u> The energy of one photon of the given light is 3.79\times 10^{-19}J

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To calculate the energy of one photon, we use Planck's equation, which is:

E=\frac{hc}{\lambda}

where,

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h = Planck's constant = 6.625\times 10^{-34}J.s

c = speed of light = 3\times 10^8m/s

Putting values in above equation, we get:

E=\frac{6.625\times 10^{-34}J.s\times 3\times 10^8m/s}{5.25\times 10^{-7}mm}\\\\E=3.79\times 10^{-19}J

Hence, the energy of one photon of the given light is 3.79\times 10^{-19}J

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