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Musya8 [376]
1 year ago
5

According to the beer-lambert law, what happens to the absorbance value of a light-absorbing chemical when its concentration inc

reases?.
Chemistry
1 answer:
Nana76 [90]1 year ago
5 0

According to the beer-lambert law when its concentration increases  so does the absorbance increase.

beer-lambert law states that the amount of energy absorbed or transferred by a solution is proportional to the molar absorptivity of the solution and the concentration of the solute.

This means that concentrated solutions absorb more light than dilute solutions.

so the According to the beer-lambert law concentration increases, so does the absorbance. Therefore, absorbance is directly proportional to concentration.

learn more about beer-lambert law at brainly.com/question/8831959

#SPJ4

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The small flag indicating wind direction on a station weather plot points in the direction that the wind is going.
Gnoma [55]

Answer:

False

Explanation: The wind's direction is shown by a long shaft. it will point to the direction from which direction the wind is blowing.

3 0
2 years ago
Read 2 more answers
Which of the following characteristics is the kinetic molecular theory based on? Matter does not have motion. All matter is in c
solmaris [256]

Answer:

All matter is in continual random motion.

Explanation:

Because Kinetic Molecular theory is based on a principle idea that tiny particles such as gas particles are always in motion.

4 0
3 years ago
A glass cylinder contains 2 gases at a pressure of 106 kPa. If one gas is at 7 kPa, what is the pressure of attributed to the ot
Ivan

Answer:

b) 99 kPa

Explanation:

According to Daltons law of partial pressure, the total pressure of a mixture of two or more non reactive gases is the sum of their individual pressures. Let the total pressure of a mixture of n number of gases be P_{total} and their individual pressure be P_1,P_2,P_3,\ .\ .\ .\ ,\ P_n, According to Daltons partial pressure law:

P_{total}=P_1+P_2+P_3+.\ .\ .+P_n

Since A glass cylinder contains 2 gases at a pressure of 106 kPa, therefore n = 2. Also one gas (P_1) is at 7 kPa. Using Daltons partial pressure law:

P_{total}=P_1+P_2+P_3+.\ .\ .+P_n\\P_{total}=P_1+P_2\\106\ kPa=7\ kPa+P_2\\P_2=106\ kPa-7\ kPa\\P_2=99\ kPa

7 0
3 years ago
How much heat is required to raise 36 g ice at – 10.0oC to steam at 110oC? (get your answers from question #1)
Gnom [1K]

Answer:

The total heat required to raise ice at -10°C to steam at 110°C = 91606.8 J

Explanation:

The heat involved in this process involves the following:

1. Heat to change ice at -10°C to ice at 0°C;

2. Heat to change ice at 0°C to water at 0°C

3. Heat to change water at 0°C to water at 100°C

4. Heat to change water at 100°C to steam at 100°C

5. Heat to change steam at 100°C to steam at 110°C

Specific heat capacity of ice, c = 2040 J/K/kg, Latent heat of fusion of ice, L = 3.35 × 10⁵ J/kg, specific heat capacity of water, c =  4182 J/K/kg, latent heat of vaporization of water, l = 2.26 × 10⁶ J/kg, specific heat capacity of steam, c = 1996 J/K/kg

Step 1: H = mcθ; where m = 30.0 g = 0.03 g, c = 2040 J/K/kg, θ = (0 -  -10) = 10 K

H = 0.03 * 2040 * 10 = 612 J

Step 2: H = mL, where  L = 3.35 × 10⁵ J/kg

H = 0.03 * 3.35 × 10⁵ = 10050 J

Step 3: H = mcθ, where c =  4182 J/K/kg, θ = (100 - 0) = 100 K

H = 0.03 * 4182 * 100 = 12546 J

Step 4: H = ml, where l = 2.26 × 10⁶

H = 0.03 * 2.26 × 10⁶ = 67800 J

Step 5: H = mcθ, where c = 1996 J/K/kg, θ = (110 - 100) = 10 K

H = 0.03 * 1996 * 10 = 598.8 J

Total heat required to raise ice at -10°C to steam at 110°C = (612 + 10050 + 12546 + 67800 + 598.8) J = 91606.8 J

Therefore, the total heat required to raise ice at -10°C to steam at 110°C = 91606.8 J

8 0
2 years ago
Force = 2.32 N<br> Acceleration = 0.19 m/s2<br> Mass= ?
pochemuha

m=f/a, so m=2.32/.19

4 0
3 years ago
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