Ammonia gas will have a mass of 3.17grams.
HOW TO CALCULATE MASS:
- The mass of a substance can be calculated by multiplying the number of moles in the substance by its molar mass.
- However, to calculate the number of moles present in the ammonia gas given in this question, we use the formula as follows:
where;
- P = pressure (atm)
- V = volume (L)
- n = number of moles (mol)
- R = gas law constant
- T = temperature
n = PV ÷ RT
n = (1.2 × 3.7) ÷ (0.0821 × 290)
n = 4.44 ÷ 23.81
n = 0.186mol
- Mass of ammonia gas = 3.17g
- Therefore, the mass of ammonia gas is 3.17grams.
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Explanation:
The water is a polar solvent which means it strongly interact with the ionic species dissolved in it. The reason is due to the formation of Hydrogen bonding. Hence, the ionic species are known to be stabilized by solvation.
The H- bonding is the interaction of H-atom of solvent molecules with the electronegative atom of same molecule or, solute species. Ionic solutes dissolve by forming H- bonding.
But in case n- pentane which is a non polar and lack of H-atom attached to electronegative atom. Hence, there is no H- bonding.
Thus, the energy required to separate Na+ and Cl- ion would be huge in water compared to n-pentane.
Answer:
3grams
Explanation:
The reaction for the production of Magnesium dioxide will be
Mg + O2 → MgO
we have 5g of MgO (molar mass 40g)
no of moles of MgO = 5/40 = 0.125
Using unitary method we have
1 mole of Mg require 1 mole of MgO
0.125 Mole of MgO = 0.125mole of Mg
n = given mass /molar mass
0.125 = mass / molar mass
mass = 0.125* 24 = 3grams