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1 year ago

Hi, in need of a little assistance.Question: calculate the internal area of the living room.

Mathematics

1 answer:

Dominik [7]1 year ago

7 0

The living room is rectangular. We would find the area by applying the formula for calculating the area of a rectangle which is expressed as

Area = length x width

From the information given,

internal length = 5.2

internal width = 2.95

Thus,

internal area of the living room = 5.2 x 2.95

internal area of the living room = 15.34 m^2

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Joseph loves the Tennessee Titans, so his mother decides to buy

dimulka [17.4K]

Answer:

Step-by-step explanation:

question one: his mom will pay $2.1 in taxes

thats all i can answer

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3 years ago

If a circle has a diameter of two what would the area be

Feliz [49]

Answer:

3.14

Step-by-step explanation:

d=2

A= pi*r^2 = pi*(d/2)^2 = pi*(2/2)^2= pi*1 =pi =3.14

4 0

3 years ago

Using a graphing utility, find the exact solutions of the system. Round to the nearest hundredth and choose a solution to the sy

Margaret [11]

Answer:

Part 1) The exact solutions are

$(\frac{-1+\sqrt{21}} {2},4+\sqrt{21})$ and $(\frac{-1-\sqrt{21}} {2},4-\sqrt{21})$

Part 2) (1.79, 8.58)

Step-by-step explanation:

we have

$y=x^{2} +3x$ ----> equation A

$y=2x+5$ ----> equation B

we know that

When solving the system of equations by graphing, the solution of the system is the intersection points both graphs

Find the exact solutions of the system

equate equation A and equation B

$x^{2} +3x=2x+5\\x^{2} +3x-2x-5=0\\x^{2} +x-5=0$

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$x^{2} +x-5=0$

$a=1\\b=1\\c=-5$

substitute in the formula

$x=\frac{-1\pm\sqrt{1^{2}-4(1)(-5)}} {2(1)}$

$x=\frac{-1\pm\sqrt{21}} {2}$

The solutions are

$x_1=\frac{-1+\sqrt{21}} {2}$

$x_2=\frac{-1-\sqrt{21}} {2}$

Find the values of y

First solution

For $x_1=\frac{-1+\sqrt{21}} {2}$

$y=2(\frac{-1+\sqrt{21}} {2})+5$

$y=-1+\sqrt{21}+5\\\\y=4+\sqrt{21}$

The first solution is the point $(\frac{-1+\sqrt{21}} {2},4+\sqrt{21})$

Second solution

For $x_2=\frac{-1-\sqrt{21}} {2}$

$y=2(\frac{-1-\sqrt{21}} {2})+5$

$y=-1-\sqrt{21}+5\\\\y=4-\sqrt{21}$

The second solution is the point $(\frac{-1-\sqrt{21}} {2},4-\sqrt{21})$

Round to the nearest hundredth

First solution

$(\frac{-1+\sqrt{21}} {2},4+\sqrt{21})$ -----> $(1.79,8.58)$

$(\frac{-1-\sqrt{21}} {2},4-\sqrt{21})$ -----> $(-2.79,-0.58)$

see the attached figure to better understand the problem

6 0

3 years ago

Explain how finding 7x20 is similar to finding 7 x 2,000. Then find each product

Sphinxa [80]

7×20 and 7×2000 are similar. The amount of zeros are the dependent factor.

7×20= 140
7×2000= 14000

The base equation is 7×2=14
Any additions of zeroes in this formula will be added at the end result.

Ex.
7×2=14
7×20=140
7×200=1400
70×200=14000
700×200=140000

5 0

3 years ago

Please help this is my last one

stiks02 [169]

Answer:

(4,1)

Step-by-step explanation:

If you have any questions about the way I solved it, don't hesitate to ask me in the comments below :)

6 0

3 years ago