2+½, is just 2½, now divided by 1/4.
let's first convert the mixed fraction to improper, and then divide.
![\bf \stackrel{mixed}{2\frac{1}{2}}\implies \cfrac{2\cdot 2+1}{2}\implies \stackrel{improper}{\cfrac{5}{2}} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{5}{2}\div \cfrac{1}{4}\implies \cfrac{5}{2}\cdot \cfrac{4}{1}\implies \cfrac{5}{1}\cdot \cfrac{4}{2}\implies 5\cdot 2\implies 10](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7Bmixed%7D%7B2%5Cfrac%7B1%7D%7B2%7D%7D%5Cimplies%20%5Ccfrac%7B2%5Ccdot%202%2B1%7D%7B2%7D%5Cimplies%20%5Cstackrel%7Bimproper%7D%7B%5Ccfrac%7B5%7D%7B2%7D%7D%0A%5C%5C%5C%5C%5B-0.35em%5D%0A~%5Cdotfill%5C%5C%5C%5C%0A%5Ccfrac%7B5%7D%7B2%7D%5Cdiv%20%5Ccfrac%7B1%7D%7B4%7D%5Cimplies%20%5Ccfrac%7B5%7D%7B2%7D%5Ccdot%20%5Ccfrac%7B4%7D%7B1%7D%5Cimplies%20%5Ccfrac%7B5%7D%7B1%7D%5Ccdot%20%5Ccfrac%7B4%7D%7B2%7D%5Cimplies%205%5Ccdot%202%5Cimplies%2010)
Y = 12% = 0.12
y = 100(0.05) + x(0.2) / 100 + x
0.12 = 5 + 0.2x / 100 + x
0.12( 100 + x ) = 5 + 0.2x
12 + 0.12x = 5 + 0.2x
7 = 0.08x
x = 87.5
hope this help
F incenter hope this helps
-6/5 is the slope. you start at point (0,0) and then move down 6 units and to the right 5 units and then create one point. from that point, go down 6 units and to the right 5 units and repeat. when you reach the bottom of the graph stop. go back to (0,0) and then move up 6 units and to the left 5 units. connect the points with a ruler and add arrows to each side. label your line with "y=-6/5x" on the line
<span>Commutative Property is the property in which you can move around numbers in numerical operations like, addition and multiplication while retaining their result. In contrast to subtraction and division in which position is an important factor for every result, here it is regardless. </span>Why might you want to use this property?<span>Well, most importantly it suits the operation of addition and hence, to ensure the arrangement of the number is in symmetric proportion to its counterpart such as 3 + 2=2 + 3. Or rather, understanding that the equations in both sides are but the same and equal in sum. Thus, this is much more usable or will make more sense if used in a larger scale of complex equations and integers.<span>
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