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fiasKO [112]
2 years ago
8

Within each year, what is the pattern of change in CO₂ concentration? Why does this pattern occur?

Biology
1 answer:
telo118 [61]2 years ago
7 0

The pattern of change in CO₂ concentration is new plant growth in the spring increases photosynthesis rates, which lowers CO2 concentrations; this decline continues until autumn, when leaves fall and decompose, raising CO2 concentrations.

The level of carbon dioxide within the surroundings rises and falls every 12 months as plant life, thru photosynthesis and respiration, absorbs the gas in the spring and summer season, and launches it in fall and wintry weather. Now the range of that cycle is expanding as extra carbon dioxide is emitted from burning fossil fuels and different human activities.

In spring, flora in the Northern Hemisphere starts to develop and absorb CO2 from the atmosphere, so atmospheric CO2 attention decreases as the road dives down. In fall, flora starts to decay and release their CO2 again into the ecosystem, so atmospheric CO2 attention increases the line shoots up. plants are accumulating carbon within the spring and summer while they are lively, and they're liberating carbon again to the air in the fall and winter.

Learn more about patterns that occur here:-https://brainly.ph/question/6286565

#SPJ4

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Answer:

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Is the pit that marks where the umbilical cord was attached before birth?
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3 years ago
Two linked genes, A and B, are separated by 18 cM. A man with genotype AB/ab marries a woman who is ab/ab. The man’s father was
kolbaska11 [484]

Answer:

a) 9%.  

b) 16.8%.

Explanation:

a).

We are provided with the information that Two linked genes, A and B, are separated by 18 cM (centiMorgan). i.e the recombinant frequency is 18%

Also , the man's genotype is AB/ab... This only result to one explanation, that The man will definitely produce 18% of recombinant gametes which entails

9% Ab & 9% aB

i.e 0.09 Ab & 0.09 aB

On the other-hand, The mother ab/ab have tendency to produce just one single type of gamete which is ab

∴

The probability that their first child will be Ab/ab will be

Pr ( Ab/ab) = (0.09) x (1)

= 0.09

= 9%.  

b).

If the father produces 18% of recombinant gametes which entails

9% Ab & 9% aB , this typically implies that the number of the non-recombinant gametes will be;

100%-18% = 82%  ( non-recombinant gametes)

i.e genotype AB/ab = 82%

AB =41%; ab = 41%

AB = 0.41 ; ab = 0.41

Now, the probability that their first two children will both be ab/ab:

Using Multiplication Rule to calculate the probability that their first two children (ab/ab); we have:

 (0.41)(1) ×(0.41)(1)

= 0.1681

= 16.8%.

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