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2 years ago

Find the value of 4x + 3y when x = 13 and y=9

Mathematics

2 answers:

Ilia_Sergeevich [38]2 years ago

8 0

Answer:

Step-by-step explanation:

The equation would now be 4(13) + 3(9). This can be simplified to 52 + 27. Solving this, you get 79.

Hope it helps!

Talja [164]2 years ago

5 0

Answer:

Step-by-step explanation:

4(13)+3(9)

52+27

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1+secA/sec A = sin^2 A / 1-cos A

Fofino [41]

Answer: see proof below

<u>Step-by-step explanation:</u>

$\dfrac{1+\sec A}{\sec A}=\dfrac{\sin^2 A}{1-\cos A}$

Use the following Identities:

sec Ф = 1/cos Ф

cos² Ф + sin² Ф = 1

<u>Proof LHS → RHS</u>

$\text{LHS:}\qquad \qquad \dfrac{1+\sec A}{\sec A}$

$\text{Identity:}\qquad \qquad \dfrac{1+\frac{1}{\cos A}}{\frac{1}{\cos A}}$

$\text{Simplify:}\qquad \qquad \dfrac{\frac{\cos A+1}{\cos A}}{\frac{1}{\cos A}}\\\\\\.\qquad \qquad \qquad =\dfrac{1+\cos A}{1}$

$\text{Multiply:}\qquad \qquad \dfrac{1+\cos A}{1}\cdot \bigg(\dfrac{1-\cos A}{1-\cos A}\bigg)\\\\\\.\qquad \qquad \qquad =\dfrac{1-\cos^2 A}{1-\cos A}$

$\text{Identity:}\qquad \qquad \dfrac{\sin^2 A}{1-\cos A}$

$\text{LHS = RHS:}\quad \dfrac{\sin^2 A}{1-\cos A}=\dfrac{\sin^2 A}{1-\cos A}\quad \checkmark$

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3 years ago

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Zanzabum

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Tems11 [23]

Answer:

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Step-by-step explanation:

14 + x = 84

x= 84 - 14

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Step-by-step explanation:

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