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alexdok [17]
1 year ago
11

8 children have to share two thirds of a watermelon equally what part of the whole watermelon would each child get

Mathematics
1 answer:
Vitek1552 [10]1 year ago
5 0

Each child would get 1/12 th part of the whole watermelon.

For given question,

8 children have to share two thirds of a watermelon equally .

This means we need to equally distribute 2/3 of whole watermelon to 8 children.

To divide 2/3 part of of a watermelon equally into 8 parts, we need to divide 2/3 by 8.

(2/3) ÷ 8

= \frac{(\frac{2}{3} )}{8}

We know that in 8 = 8/1

So, we rewrite the denominator of above fraction as,

\frac{(\frac{2}{3} )}{8} \\\\= \frac{(\frac{2}{3} )}{(\frac{8}{1} )} \\\\=\frac{2}{3} \times \frac{1}{8} \\\\=\frac{1}{12}

This means, each child will get 1/12 part of the whole watermelon.

Therefore, each child would get 1/12 part of the whole watermelon.

Learn more about the fraction here:

brainly.com/question/8969674

#SPJ4

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<h2>Answer:</h2>

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<h2>Step-by-step explanation:</h2>

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Where;

A = 18\sqrt{3}

b = XZ = base of the triangle

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<em>Substitute these values into equation(i) and solve as follows:</em>

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18\sqrt{3} =  3b

<em>Divide through by 3</em>

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(ii) XZO = ZXO = 30°

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=>  XOZ + 30° + 30° = 180°

=>  XOZ + 60° = 180°

=>  XOZ = 180° - 60°

=>  XOZ = 120°

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\frac{sin|XOZ|}{XZ} = \frac{sin|ZXO|}{OZ}

\frac{sin120}{6\sqrt{3} } = \frac{sin 30}{OZ}

\frac{\sqrt{3} /2}{6\sqrt{3} } = \frac{1/2}{|OZ|}

\frac{1}{12}  = \frac{1}{2|OZ|}

\frac{1}{6} = \frac{1}{|OZ|}

|OZ| = 6

The radius of the circle is therefore 6.

<em>Now, let's calculate the length of the arc XZ</em>

The length(L) of an arc is given by;

L = θ / 360 x 2 π r          ------------------(ii)

Where;

θ = angle subtended by the arc at the center.

r = radius of the circle.

In our case,

θ = ZOX = 120°

r = |OZ| = 6

Substitute these values into equation (ii) as follows;

L = 120/360 x 2π x 6

L = 4π

Therefore the length of the arc XZ is 4π

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