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blondinia [14]
1 year ago
10

Need this quick ! Correct answers appreciated

Mathematics
1 answer:
ludmilkaskok [199]1 year ago
4 0
5

g(f(-5))
g( | 2 * -5 + 9 | )
g( |-1| )
g(1)
5
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BRAINLIESTTT ASAP!! PLEASE HELP ME :)
Tju [1.3M]

Answer:

Choice C.

Step-by-step explanation:

A parallelogram is a quadrilateral with two pairs of opposite parallel sides.

There is a theorem that states that opposite sides of a parallelogram are congruent.

In this case, sides AB and CD are opposite sides.

Sides BC and AD are opposite sides.

Side CD is opposite side AB, so they are congruent.

Answer:

Choice C.

CD = AB; Opposite sides of parallelograms are congruent.

5 0
3 years ago
Help please i really need it asap
Varvara68 [4.7K]
The expression coud be re written:

12x²y/2xy + 6xy/2xy + 4x²/2xy . Simplify numerator & denominator whenever it is possible:

6x-3+2x/y
3 0
3 years ago
I GIVE BRAINLIEST PLS HELP
ioda
The answer is 8
Here's why:
{ ( \frac{( {6}^{7}) \times ( {3}^{3})  }{(  {6}^{6}) \times ( {3}^{4}  ) } )}^{3}  =   \\ ( \frac{6}{3} ) ^{3}  =  \\ \frac{216}{27}  = 8
The exponents are subtracted one from another when divided.
\frac{ a ^{b} }{ {a}^{c} } =  {a}^{b - c}
We can look at the problem this way:
( \frac{6^{7} }{6 ^{6} }  \times  \frac{3^{3} }{ {3}^{4} } ) = (6^{7 - 6}  \times  {3}^{3 - 4} ) =  \\ ({6}^{1}  \times  {3}^{ - 1} )
Since we have the power of -1 on the 3, we apply this rule:
{a}^{ - b}  =  \frac{1}{ {a}^{b} }
Also this rule because we have the power of 1 on the 6:
{a}^{1}  = a
Then we get this:
(6 \times  \frac{1}{3} )^{3}  = ( \frac{6}{3} )^{3}
We apply the rule:
( \frac{a}{b}) ^{c}   =  \frac{ {a}^{c} }{ {b}^{c} }
We get this:
\frac{{6}^{3} }{ {3}^{3} } =  \frac{216}{27}  = 8
4 0
4 years ago
Rephrase in contrapositive form:
miv72 [106K]

Step-by-step explanation:

Consider the provided information.

For the condition statement p \rightarrow q or equivalent "If p then q"

The rule for Contrapositive is: Negative both statements and interchange them. \sim q \rightarrow \sim p

Part (A) If you are taller than 6 ft, then it is unpleasant for you to travel in economy class.

Here p is "you are taller than 6 ft, and q is "it is unpleasant for you to travel in economy class".

It is given that Your contrapositive must not contain explicit references to negation. Assume that the negation of "unpleasant" is "pleasant".

Contrapositive: If it is pleasant for you to travel in economy class then you are not taller than 6 ft then.

Part (B) "If x ≥ 0 and y ≥ 0 then xy ≥ 0" where x, y are real numbers.

Here p is "xy≥ 0, and q is "x ≥ 0 and y ≥ 0"

The negative of xy≥ 0 is xy<0, x ≥ 0 is x<0 and y ≥ 0 is y<0.

Remember negative means opposite.

Contrapositive: If xy < 0 then x<0 and y<0.

8 0
3 years ago
12.) 15 + (-15) + 12
erica [24]
15-15+12
0+12
12
.........
6 0
4 years ago
Read 2 more answers
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